Mister Exam

Lang:

How to use it?
Factor polynomial:
z^3+i^3
z^3+8*i
z^3-6*z^2+5*z+12
z^3+5*z^2+4*z-10
Least common denominator:
(z^2-2*t+2*t1+exp(t1/t)*(2*t-z^2))*(z^2-2*t+2*t2+exp(t2/t)*(2*t-z^2))
((z^2+1)^2/(4*z^2))/(13+12*((z^2+1)/2*z*z))
-z/1-z/2
y*(y+((1/(x+(x^2+y^2)^(1/2))*(1+(2*x/(2*(x^2+y^2)^(1/2)))))))-(y/(x^2+y^2)^(1/2))
Factor squared:
-y^4+y^2+2
y^4-y^2-13
-y^4-8*y^2-2
-y^4-8*y^2-4
How do you in partial fractions?:
(1-x/(1+x))/(1+x)^3
(x^2+6*x+8)/(x+4)
(c^4)^5*c^8/(c^7)^4
-3/(x*x^3)
Identical expressions
z^ three + eight *i
z cubed plus 8 multiply by i
z to the power of three plus eight multiply by i
z3+8*i
z³+8*i
z to the power of 3+8*i
z^3+8i
z3+8i
Similar expressions
z^3-8*i

Factor polynomial z^3+8*i

You have entered [src]

 3      
z  + 8*I

$$z^{3} + 8 i$$

z^3 + 8*i

Factorization [src]

          /          ___\ /        ___    \
(x - 2*I)*\x + I + \/ 3 /*\x + - \/ 3  + I/

$$\left(x - 2 i\right) \left(x + \left(\sqrt{3} + i\right)\right) \left(x + \left(- \sqrt{3} + i\right)\right)$$

((x - 2*i)*(x + i + sqrt(3)))*(x - sqrt(3) + i)

Numerical answer [src]

z^3 + 8.0*i

z^3 + 8.0*i