Mister Exam
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How to use it?
How do you in partial fractions?
:
(z^2-4*z+16)/(16*z^2-1)*(4*z^2+z)/(z^3+64)-(z+4)/(4*z^2-z)
(5x^2+9x-2)/(x^2-5x-14)
y/(y+2)+(1/(4-y^2)-1/(4-4*y+y^2))/(2/(y-2)^2)
1/(2*sqrt(x))
Factor polynomial
:
x^2+3
x^4-x
x*y^3-x^3*y^2
x^2-1
Least common denominator
:
4*x^(3/2)/3+2*sqrt(x)+x^5/5+e^(5*x^3+1)/15
z*((-z)*log(x)/c+z*log(y)/c)
(z*z-1/2*z)/(z*z-z+1)*z/(z-1/2)
-x^2/(x-2)^2+2*x/(x-2)
Factor squared
:
y^4+y^2+2
y^4+y^2-15
y^4-y^2-5
-y^4+8*y^2-8
Integral of d{x}
:
1/(2*sqrt(x))
Derivative of
:
1/(2*sqrt(x))
Identical expressions
one /(two *sqrt(x))
1 divide by (2 multiply by square root of (x))
one divide by (two multiply by square root of (x))
1/(2*√(x))
1/(2sqrt(x))
1/2sqrtx
1 divide by (2*sqrt(x))
Similar expressions
1/(2*sqrt(x)*(1+x))
-1/(2*sqrt(x)*(1+x))
1/2+(sqrt(x)+1)/(2*sqrt(x))
(1+1/x)*(1/(2*sqrt(x)+2)+1/(2-2*sqrt(x))-(x^2+1)/(1-x^2))
Expression simplification
/
Fraction Decomposition into the simple
/
1/(2*sqrt(x))
How do you 1/(2*sqrt(x)) in partial fractions?
An expression to simplify:
Decompose fraction
The solution
You have entered
[src]
1 ------- ___ 2*\/ x
$$\frac{1}{2 \sqrt{x}}$$
1/(2*sqrt(x))
Fraction decomposition
[src]
1/(2*sqrt(x))
$$\frac{1}{2 \sqrt{x}}$$
1 ------- ___ 2*\/ x
Rational denominator
[src]
___ \/ x ----- 2*x
$$\frac{\sqrt{x}}{2 x}$$
sqrt(x)/(2*x)
Numerical answer
[src]
0.5*x^(-0.5)
0.5*x^(-0.5)