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How to use it?
How do you in partial fractions?
:
2*x/(x^2+1)-2*x*(x^2-1)/(x^2+1)^2
(x^2-6*x+8)/(x-4)
1/(2*sqrt(x))
(x^2-6*x+8)/(x+4)
Factor polynomial
:
x^6-x^4*y^2-x^3+x^2*y
z^3+2*z^2+6*z-9
z^2+9
x^2-7
Least common denominator
:
(z/b+b/z)/z2+b2/6*z10*b
z-8/z^2/3*z^(1/3)+4
(z^5-5*z^3+10*z-10/z+1/5*z^3-1/z^5)*(z^3-3*z+3/z-1/z^3)
y/(x-y)+x/(y-x)
Factor squared
:
y^4+9*y^2+3
-y^4-9*y^2+15
y^4-y^2-6
y^4-7*y^2+4
Integral of d{x}
:
1/(2*sqrt(x))
Derivative of
:
1/(2*sqrt(x))
Identical expressions
one /(two *sqrt(x))
1 divide by (2 multiply by square root of (x))
one divide by (two multiply by square root of (x))
1/(2*√(x))
1/(2sqrt(x))
1/2sqrtx
1 divide by (2*sqrt(x))
Similar expressions
1/(2*sqrt(x)*(1+x))
(1+1/x)*(1/(2*sqrt(x)+2)+1/(2-2*sqrt(x))-(x^2+1)/(1-x^2))
1/2+(sqrt(x)+1)/(2*sqrt(x))
-1/(2*sqrt(x)*(1+x))
Expression simplification
/
Fraction Decomposition into the simple
/
1/(2*sqrt(x))
How do you 1/(2*sqrt(x)) in partial fractions?
An expression to simplify:
Decompose fraction
The solution
You have entered
[src]
1 ------- ___ 2*\/ x
$$\frac{1}{2 \sqrt{x}}$$
1/(2*sqrt(x))
Fraction decomposition
[src]
1/(2*sqrt(x))
$$\frac{1}{2 \sqrt{x}}$$
1 ------- ___ 2*\/ x
Rational denominator
[src]
___ \/ x ----- 2*x
$$\frac{\sqrt{x}}{2 x}$$
sqrt(x)/(2*x)
Numerical answer
[src]
0.5*x^(-0.5)
0.5*x^(-0.5)