Mister Exam
Other calculators
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How to use it?
- Factor squared:
- y^4+y^2-3
- y^4+y^2+4
- y^4-12*y^2+7
- y^2+4*y-3
- Factor polynomial:
- y^3+y^5
- x^3-x
- x1^2+x2^2
- x^3+7*x^2+15*x+9
- Least common denominator:
- (x*(x-6)^2)^(1/3)*((x-6)^2/3+x*(-12+2*x)/3)/(x*(x-6)^2)
- (a-3+18/a+3)/a^2+9/a^2+6*a+9/a-3
- 5*(2-2/x^2)*cos(2*x+2/x)
- (2*a+b)/(a^2-b^2)+1/(a+b)
- How do you in partial fractions?:
- (z-(5*z)/z+1)/(z-4)/(z+1)
- 1/(1+x^2/3)
- (x^2-5*x+6)/(x-3)
- ((z^2-49)/(2*z^2+1))*(((14*z+1)/(z-7))+((14*z-1)/(z+7)))
- Derivative of:
-
x^2-x+2
- Equation:
- x^2-x+2
- Factor polynomial:
- x^2-x+2
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Identical expressions
- x^ two -x+ two
- x squared minus x plus 2
- x to the power of two minus x plus two
- x2-x+2
- x²-x+2
- x to the power of 2-x+2
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Similar expressions
- x^2+x+2
- x^2-x-2
Factor x^2-x+2 squared
The solution
Factorization
[src]
/ ___\ / ___\ | 1 I*\/ 7 | | 1 I*\/ 7 | |x + - - + -------|*|x + - - - -------| \ 2 2 / \ 2 2 /
$$\left(x + \left(- \frac{1}{2} - \frac{\sqrt{7} i}{2}\right)\right) \left(x + \left(- \frac{1}{2} + \frac{\sqrt{7} i}{2}\right)\right)$$
(x - 1/2 + i*sqrt(7)/2)*(x - 1/2 - i*sqrt(7)/2)
The perfect square
Let's highlight the perfect square of the square three-member
$$\left(x^{2} - x\right) + 2$$
To do this, let's use the formula
$$a x^{2} + b x + c = a \left(m + x\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = 1$$
$$b = -1$$
$$c = 2$$
Then
$$m = - \frac{1}{2}$$
$$n = \frac{7}{4}$$
So,
$$\left(x - \frac{1}{2}\right)^{2} + \frac{7}{4}$$
$$\left(x^{2} - x\right) + 2$$
To do this, let's use the formula
$$a x^{2} + b x + c = a \left(m + x\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = 1$$
$$b = -1$$
$$c = 2$$
Then
$$m = - \frac{1}{2}$$
$$n = \frac{7}{4}$$
So,
$$\left(x - \frac{1}{2}\right)^{2} + \frac{7}{4}$$