Mister Exam
Other calculators
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How to use it?
- Factor squared:
- -y^4+y^2-4
- y^4+y^2+3
- x^2-x+2
- x^2-x-3
- Factor polynomial:
- x^5+y^5+z^5
- x+x^8/8
- x-x^2
- x^5-32
- Least common denominator:
- 2/(a+2)+(a-2)/(a^2+4*a+4)/(a/(2*a-4)+(a^2+4)/(8-2*a)-2/(2*a+a^2))
- (234/(((7/20)*p+1)*(p+1)*((111/10)*p+1)))*((3/10)+10/p)
- (z*z-1/2*z)/(z*z-z+1)*z/(z-1/2)
- (z/x-z+x+z/z)/x/x^2-z^2
- How do you in partial fractions?:
- (x^2-9)/(x+3)
- (z-3)/(z+3)*(z+(z^2)/(3-z))
- (y^2-16)/(4*y^2-y^3)
- (x^2-x-12)/(x+3)
- Factor polynomial:
- x^2-x+2
- Equation:
- x^2-x+2
- Derivative of:
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x^2-x+2
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Identical expressions
- x^ two -x+ two
- x squared minus x plus 2
- x to the power of two minus x plus two
- x2-x+2
- x²-x+2
- x to the power of 2-x+2
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Similar expressions
- x^2+x+2
- x^2-x-2
Factor x^2-x+2 squared
The solution
Factorization
[src]
/ ___\ / ___\ | 1 I*\/ 7 | | 1 I*\/ 7 | |x + - - + -------|*|x + - - - -------| \ 2 2 / \ 2 2 /
$$\left(x + \left(- \frac{1}{2} - \frac{\sqrt{7} i}{2}\right)\right) \left(x + \left(- \frac{1}{2} + \frac{\sqrt{7} i}{2}\right)\right)$$
(x - 1/2 + i*sqrt(7)/2)*(x - 1/2 - i*sqrt(7)/2)
The perfect square
Let's highlight the perfect square of the square three-member
$$\left(x^{2} - x\right) + 2$$
To do this, let's use the formula
$$a x^{2} + b x + c = a \left(m + x\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = 1$$
$$b = -1$$
$$c = 2$$
Then
$$m = - \frac{1}{2}$$
$$n = \frac{7}{4}$$
So,
$$\left(x - \frac{1}{2}\right)^{2} + \frac{7}{4}$$
$$\left(x^{2} - x\right) + 2$$
To do this, let's use the formula
$$a x^{2} + b x + c = a \left(m + x\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = 1$$
$$b = -1$$
$$c = 2$$
Then
$$m = - \frac{1}{2}$$
$$n = \frac{7}{4}$$
So,
$$\left(x - \frac{1}{2}\right)^{2} + \frac{7}{4}$$