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How do you x/(x^3-1) in partial fractions?

You have entered [src]

  x   
------
 3    
x  - 1

$$\frac{x}{x^{3} - 1}$$

x/(x^3 - 1)

Fraction decomposition [src]

1/(3*(-1 + x)) - (-1 + x)/(3*(1 + x + x^2))

$$- \frac{x - 1}{3 \left(x^{2} + x + 1\right)} + \frac{1}{3 \left(x - 1\right)}$$

    1            -1 + x    
---------- - --------------
3*(-1 + x)     /         2\
             3*\1 + x + x /

Numerical answer [src]

x/(-1.0 + x^3)

x/(-1.0 + x^3)

Combinatorics [src]

          x          
---------------------
         /         2\
(-1 + x)*\1 + x + x /

$$\frac{x}{\left(x - 1\right) \left(x^{2} + x + 1\right)}$$

x/((-1 + x)*(1 + x + x^2))