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How do you x^2-9/(x+3)^2 in partial fractions?

An expression to simplify:

The solution

You have entered [src]
 2      9    
x  - --------
            2
     (x + 3) 
$$x^{2} - \frac{9}{\left(x + 3\right)^{2}}$$
x^2 - 9/(x + 3)^2
Fraction decomposition [src]
x^2 - 9/(3 + x)^2
$$x^{2} - \frac{9}{\left(x + 3\right)^{2}}$$
 2      9    
x  - --------
            2
     (3 + x) 
Combinatorics [src]
/      2      \ /     2      \
\-3 + x  + 3*x/*\3 + x  + 3*x/
------------------------------
                  2           
           (3 + x)            
$$\frac{\left(x^{2} + 3 x - 3\right) \left(x^{2} + 3 x + 3\right)}{\left(x + 3\right)^{2}}$$
(-3 + x^2 + 3*x)*(3 + x^2 + 3*x)/(3 + x)^2
Numerical answer [src]
x^2 - 1.0/(1 + 0.333333333333333*x)^2
x^2 - 1.0/(1 + 0.333333333333333*x)^2
Combining rational expressions [src]
      2        2
-9 + x *(3 + x) 
----------------
           2    
    (3 + x)     
$$\frac{x^{2} \left(x + 3\right)^{2} - 9}{\left(x + 3\right)^{2}}$$
(-9 + x^2*(3 + x)^2)/(3 + x)^2
Rational denominator [src]
      2        2
-9 + x *(3 + x) 
----------------
           2    
    (3 + x)     
$$\frac{x^{2} \left(x + 3\right)^{2} - 9}{\left(x + 3\right)^{2}}$$
(-9 + x^2*(3 + x)^2)/(3 + x)^2
Common denominator [src]
 2        9      
x  - ------------
          2      
     9 + x  + 6*x
$$x^{2} - \frac{9}{x^{2} + 6 x + 9}$$
x^2 - 9/(9 + x^2 + 6*x)