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Factor x^4-2*x^2-1 squared

An expression to simplify:

The solution

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 4      2    
x  - 2*x  - 1
$$\left(x^{4} - 2 x^{2}\right) - 1$$
x^4 - 2*x^2 - 1
The perfect square
Let's highlight the perfect square of the square three-member
$$\left(x^{4} - 2 x^{2}\right) - 1$$
To do this, let's use the formula
$$a x^{4} + b x^{2} + c = a \left(m + x^{2}\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = 1$$
$$b = -2$$
$$c = -1$$
Then
$$m = -1$$
$$n = -2$$
So,
$$\left(x^{2} - 1\right)^{2} - 2$$
General simplification [src]
      4      2
-1 + x  - 2*x 
$$x^{4} - 2 x^{2} - 1$$
-1 + x^4 - 2*x^2
Factorization [src]
/         ____________\ /         ____________\ /       ___________\ /       ___________\
|        /        ___ | |        /        ___ | |      /       ___ | |      /       ___ |
\x + I*\/  -1 + \/ 2  /*\x - I*\/  -1 + \/ 2  /*\x + \/  1 + \/ 2  /*\x - \/  1 + \/ 2  /
$$\left(x - i \sqrt{-1 + \sqrt{2}}\right) \left(x + i \sqrt{-1 + \sqrt{2}}\right) \left(x + \sqrt{1 + \sqrt{2}}\right) \left(x - \sqrt{1 + \sqrt{2}}\right)$$
(((x + i*sqrt(-1 + sqrt(2)))*(x - i*sqrt(-1 + sqrt(2))))*(x + sqrt(1 + sqrt(2))))*(x - sqrt(1 + sqrt(2)))
Common denominator [src]
      4      2
-1 + x  - 2*x 
$$x^{4} - 2 x^{2} - 1$$
-1 + x^4 - 2*x^2
Numerical answer [src]
-1.0 + x^4 - 2.0*x^2
-1.0 + x^4 - 2.0*x^2
Combinatorics [src]
      4      2
-1 + x  - 2*x 
$$x^{4} - 2 x^{2} - 1$$
-1 + x^4 - 2*x^2
Combining rational expressions [src]
      2 /      2\
-1 + x *\-2 + x /
$$x^{2} \left(x^{2} - 2\right) - 1$$
-1 + x^2*(-2 + x^2)
Powers [src]
      4      2
-1 + x  - 2*x 
$$x^{4} - 2 x^{2} - 1$$
-1 + x^4 - 2*x^2
Trigonometric part [src]
      4      2
-1 + x  - 2*x 
$$x^{4} - 2 x^{2} - 1$$
-1 + x^4 - 2*x^2
Rational denominator [src]
      4      2
-1 + x  - 2*x 
$$x^{4} - 2 x^{2} - 1$$
-1 + x^4 - 2*x^2
Assemble expression [src]
      4      2
-1 + x  - 2*x 
$$x^{4} - 2 x^{2} - 1$$
-1 + x^4 - 2*x^2