Mister Exam

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How to use it?
How do you in partial fractions?:
x^(2*n)/(x^n-1)^2
2*(-4+3*(-1+2*x)/(-1+x))/(-1+x)^3
(((3*x)^3)*x^(-9))/((x^(-10))*2*x^4)
-1/x+x/(2*x+3)
Factor polynomial:
z^3+i^3
z^3+8/125
z^3-6*z^2+5*z+12
z^3+5*z^2+17*z+13
Least common denominator:
((y/x-y)+(x/x+y))*((x^2/y^2)+(y^2/x^2)-2)
(y/(x*y-x^2)+x/(x*y-y^2))/(x^2+2*x*y+y^2/(1/x+1/y))
y-b/(a-a*b)-(y-a)/a*b-b
(y/5*x-5*x-y)/(y+5*x)
Factor squared:
-y^4+8*y^2+15
-y^4+8*y^2-1
-y^4+9*y^2+6
-y^4+7*y^2+6
Identical expressions
two *(- four + three *(- one + two *x)/(- one +x))/(- one +x)^ three
2 multiply by ( minus 4 plus 3 multiply by ( minus 1 plus 2 multiply by x) divide by ( minus 1 plus x)) divide by ( minus 1 plus x) cubed
two multiply by ( minus four plus three multiply by ( minus one plus two multiply by x) divide by ( minus one plus x)) divide by ( minus one plus x) to the power of three
2*(-4+3*(-1+2*x)/(-1+x))/(-1+x)3
2*-4+3*-1+2*x/-1+x/-1+x3
2*(-4+3*(-1+2*x)/(-1+x))/(-1+x)³
2*(-4+3*(-1+2*x)/(-1+x))/(-1+x) to the power of 3
2(-4+3(-1+2x)/(-1+x))/(-1+x)^3
2(-4+3(-1+2x)/(-1+x))/(-1+x)3
2-4+3-1+2x/-1+x/-1+x3
2-4+3-1+2x/-1+x/-1+x^3
2*(-4+3*(-1+2*x) divide by (-1+x)) divide by (-1+x)^3
Similar expressions
2*(-4+3*(1+2*x)/(-1+x))/(-1+x)^3
2*(-4-3*(-1+2*x)/(-1+x))/(-1+x)^3
2*(-4+3*(-1-2*x)/(-1+x))/(-1+x)^3
2*(-4+3*(-1+2*x)/(-1-x))/(-1+x)^3
2*(-4+3*(-1+2*x)/(-1+x))/(-1-x)^3
2*(-4+3*(-1+2*x)/(-1+x))/(1+x)^3
2*(-4+3*(-1+2*x)/(1+x))/(-1+x)^3
2*(4+3*(-1+2*x)/(-1+x))/(-1+x)^3

How do you 2(-4+3(-1+2*x)/(-1+x))/(-1+x)^3 in partial fractions?

You have entered [src]

  /     3*(-1 + 2*x)\
2*|-4 + ------------|
  \        -1 + x   /
---------------------
              3      
      (-1 + x)

$$\frac{2 \left(-4 + \frac{3 \left(2 x - 1\right)}{x - 1}\right)}{\left(x - 1\right)^{3}}$$

(2*(-4 + (3*(-1 + 2*x))/(-1 + x)))/(-1 + x)^3

Fraction decomposition [src]

4/(-1 + x)^3 + 6/(-1 + x)^4

$$\frac{4}{\left(x - 1\right)^{3}} + \frac{6}{\left(x - 1\right)^{4}}$$

    4           6    
--------- + ---------
        3           4
(-1 + x)    (-1 + x)

General simplification [src]

2*(1 + 2*x)
-----------
         4 
 (-1 + x)

$$\frac{2 \left(2 x + 1\right)}{\left(x - 1\right)^{4}}$$

2*(1 + 2*x)/(-1 + x)^4

Combinatorics [src]

2*(1 + 2*x)
-----------
         4 
 (-1 + x)

$$\frac{2 \left(2 x + 1\right)}{\left(x - 1\right)^{4}}$$

2*(1 + 2*x)/(-1 + x)^4

Numerical answer [src]

(-8.0 + 2.0*(-3.0 + 6.0*x)/(-1.0 + x))/(-1.0 + x)^3

(-8.0 + 2.0*(-3.0 + 6.0*x)/(-1.0 + x))/(-1.0 + x)^3

Assemble expression [src]

     2*(-3 + 6*x)
-8 + ------------
        -1 + x   
-----------------
            3    
    (-1 + x)

$$\frac{-8 + \frac{2 \left(6 x - 3\right)}{x - 1}}{\left(x - 1\right)^{3}}$$

(-8 + 2*(-3 + 6*x)/(-1 + x))/(-1 + x)^3

Common denominator [src]

         2 + 4*x          
--------------------------
     4            3      2
1 + x  - 4*x - 4*x  + 6*x

$$\frac{4 x + 2}{x^{4} - 4 x^{3} + 6 x^{2} - 4 x + 1}$$

(2 + 4*x)/(1 + x^4 - 4*x - 4*x^3 + 6*x^2)

Rational denominator [src]

 2 + 4*x 
---------
        4
(-1 + x)

$$\frac{4 x + 2}{\left(x - 1\right)^{4}}$$

(2 + 4*x)/(-1 + x)^4

Powers [src]

     -6 + 12*x
-8 + ---------
       -1 + x 
--------------
          3   
  (-1 + x)

$$\frac{-8 + \frac{12 x - 6}{x - 1}}{\left(x - 1\right)^{3}}$$

     2*(-3 + 6*x)
-8 + ------------
        -1 + x   
-----------------
            3    
    (-1 + x)

$$\frac{-8 + \frac{2 \left(6 x - 3\right)}{x - 1}}{\left(x - 1\right)^{3}}$$

(-8 + 2*(-3 + 6*x)/(-1 + x))/(-1 + x)^3

Trigonometric part [src]

     2*(-3 + 6*x)
-8 + ------------
        -1 + x   
-----------------
            3    
    (-1 + x)

$$\frac{-8 + \frac{2 \left(6 x - 3\right)}{x - 1}}{\left(x - 1\right)^{3}}$$

(-8 + 2*(-3 + 6*x)/(-1 + x))/(-1 + x)^3

Combining rational expressions [src]

2*(1 + 2*x)
-----------
         4 
 (-1 + x)

$$\frac{2 \left(2 x + 1\right)}{\left(x - 1\right)^{4}}$$

2*(1 + 2*x)/(-1 + x)^4

How do you 2*(-4+3*(-1+2*x)/(-1+x))/(-1+x)^3 in partial fractions?