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How do you (5*x^2-3*x-2)/(5*x^2+2*x) in partial fractions?

An expression to simplify:

The solution

You have entered [src]
   2          
5*x  - 3*x - 2
--------------
     2        
  5*x  + 2*x  
$$\frac{\left(5 x^{2} - 3 x\right) - 2}{5 x^{2} + 2 x}$$
(5*x^2 - 3*x - 2)/(5*x^2 + 2*x)
General simplification [src]
-1 + x
------
  x   
$$\frac{x - 1}{x}$$
(-1 + x)/x
Fraction decomposition [src]
1 - 1/x
$$1 - \frac{1}{x}$$
    1
1 - -
    x
Numerical answer [src]
(-2.0 + 5.0*x^2 - 3.0*x)/(2.0*x + 5.0*x^2)
(-2.0 + 5.0*x^2 - 3.0*x)/(2.0*x + 5.0*x^2)
Combining rational expressions [src]
-2 + x*(-3 + 5*x)
-----------------
   x*(2 + 5*x)   
$$\frac{x \left(5 x - 3\right) - 2}{x \left(5 x + 2\right)}$$
(-2 + x*(-3 + 5*x))/(x*(2 + 5*x))
Assemble expression [src]
              2
-2 - 3*x + 5*x 
---------------
            2  
   2*x + 5*x   
$$\frac{5 x^{2} - 3 x - 2}{5 x^{2} + 2 x}$$
(-2 - 3*x + 5*x^2)/(2*x + 5*x^2)
Powers [src]
              2
-2 - 3*x + 5*x 
---------------
            2  
   2*x + 5*x   
$$\frac{5 x^{2} - 3 x - 2}{5 x^{2} + 2 x}$$
(-2 - 3*x + 5*x^2)/(2*x + 5*x^2)
Rational denominator [src]
              2
-2 - 3*x + 5*x 
---------------
            2  
   2*x + 5*x   
$$\frac{5 x^{2} - 3 x - 2}{5 x^{2} + 2 x}$$
(-2 - 3*x + 5*x^2)/(2*x + 5*x^2)
Trigonometric part [src]
              2
-2 - 3*x + 5*x 
---------------
            2  
   2*x + 5*x   
$$\frac{5 x^{2} - 3 x - 2}{5 x^{2} + 2 x}$$
(-2 - 3*x + 5*x^2)/(2*x + 5*x^2)
Common denominator [src]
    1
1 - -
    x
$$1 - \frac{1}{x}$$
1 - 1/x
Combinatorics [src]
-1 + x
------
  x   
$$\frac{x - 1}{x}$$
(-1 + x)/x