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How to use it?
How do you in partial fractions?
:
z/(2*z-4)-(z^2+4)/(2*z^2-8)-z/(z^2+2*z)
(z-3)/(z+3)*(z+(z^2)/(3-z))
2*(-1+(-1+x)/(2+x))/(2+x)^2
sqrt((w^2*(-t^2)/(1+t^2*w^2))^2+(t*w/(1+t^2*w^2))^2)
Factor polynomial
:
m^5-m^3
x^10-1
x^4-x^2+1
x^8+1
Least common denominator
:
z/x-z+x+z/z
(z-t)/(z+t)/(z-t)^2
(z/40+1/20)*(z/40+4/5)*z
((z^2-49)/(2*z^2+1))*(((14*z+1)/(z-7))+((14*z-1)/(z+7)))
Factor squared
:
-y^4-y^2+15
-y^4-y^2-11
y^4-9*y^2-3
-y^4+y^2+4
Integral of d{x}
:
(x^2-1)/(x+1)
Graphing y =
:
(x^2-1)/(x+1)
Derivative of
:
(x^2-1)/(x+1)
Identical expressions
(x^ two - one)/(x+ one)
(x squared minus 1) divide by (x plus 1)
(x to the power of two minus one) divide by (x plus one)
(x2-1)/(x+1)
x2-1/x+1
(x²-1)/(x+1)
(x to the power of 2-1)/(x+1)
x^2-1/x+1
(x^2-1) divide by (x+1)
Similar expressions
(x^2+1)/(x+1)
(x^2-1)/(x-1)
Expression simplification
/
Fraction Decomposition into the simple
/
(x^2-1)/(x+1)
How do you (x^2-1)/(x+1) in partial fractions?
An expression to simplify:
Decompose fraction
The solution
You have entered
[src]
2 x - 1 ------ x + 1
$$\frac{x^{2} - 1}{x + 1}$$
(x^2 - 1)/(x + 1)
Fraction decomposition
[src]
-1 + x
$$x - 1$$
-1 + x
General simplification
[src]
-1 + x
$$x - 1$$
-1 + x
Common denominator
[src]
-1 + x
$$x - 1$$
-1 + x
Combinatorics
[src]
-1 + x
$$x - 1$$
-1 + x
Numerical answer
[src]
(-1.0 + x^2)/(1.0 + x)
(-1.0 + x^2)/(1.0 + x)