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How to use it?
How do you in partial fractions?
:
(3*y^2-12)/(2*y^2-15*y+18)
((x+1)/(2x-3))+((x-1)/(2x+3))-((2x^2-7x)/(4x^2-9))
((p^4)^8*p^10)/((p^7)^4*p^8)
((x+1)^2/(x-1)^2)*(x-1)*(2/(x-1)-2*(x+1)/(x-1)^2)/(x+1)
Factor polynomial
:
z^3+11*z^2+36*z+26
z^2-a/z-z
z^2+9*z+27+27/z
z^2-9
Least common denominator
:
(y/5*x-5*x-y)/(y+5*x)
y^2/x^2+y/x
y^(2*n-4)*y^n/(y^n+1-5*y)-(7*y^n-30)/(y^n+1-5*y)
x*y-y/x-x*y-x/y-x2-y2/x*y
Factor squared
:
-y^4-7*y^2-15
-y^4+9*y^2-13
-y^4-8*y^2-3
-y^4+7*y^2+11
Integral of d{x}
:
x^4/(x^2+1)
Derivative of
:
x^4/(x^2+1)
Identical expressions
x^ four /(x^ two + one)
x to the power of 4 divide by (x squared plus 1)
x to the power of four divide by (x to the power of two plus one)
x4/(x2+1)
x4/x2+1
x⁴/(x²+1)
x to the power of 4/(x to the power of 2+1)
x^4/x^2+1
x^4 divide by (x^2+1)
Similar expressions
x^4/(x^2-1)
Expression simplification
/
Fraction Decomposition into the simple
/
x^4/(x^2+1)
How do you x^4/(x^2+1) in partial fractions?
An expression to simplify:
Decompose fraction
The solution
You have entered
[src]
4 x ------ 2 x + 1
$$\frac{x^{4}}{x^{2} + 1}$$
x^4/(x^2 + 1)
Fraction decomposition
[src]
-1 + x^2 + 1/(1 + x^2)
$$x^{2} - 1 + \frac{1}{x^{2} + 1}$$
2 1 -1 + x + ------ 2 1 + x
Numerical answer
[src]
x^4/(1.0 + x^2)
x^4/(1.0 + x^2)
Common denominator
[src]
2 1 -1 + x + ------ 2 1 + x
$$x^{2} - 1 + \frac{1}{x^{2} + 1}$$
-1 + x^2 + 1/(1 + x^2)