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Factor -y^4-8*y^2-3 squared

An expression to simplify:

The solution

You have entered [src]
   4      2    
- y  - 8*y  - 3
$$\left(- y^{4} - 8 y^{2}\right) - 3$$
-y^4 - 8*y^2 - 3
General simplification [src]
      4      2
-3 - y  - 8*y 
$$- y^{4} - 8 y^{2} - 3$$
-3 - y^4 - 8*y^2
Factorization [src]
/         ____________\ /         ____________\ /         ____________\ /         ____________\
|        /       ____ | |        /       ____ | |        /       ____ | |        /       ____ |
\x + I*\/  4 - \/ 13  /*\x - I*\/  4 - \/ 13  /*\x + I*\/  4 + \/ 13  /*\x - I*\/  4 + \/ 13  /
$$\left(x - i \sqrt{4 - \sqrt{13}}\right) \left(x + i \sqrt{4 - \sqrt{13}}\right) \left(x + i \sqrt{\sqrt{13} + 4}\right) \left(x - i \sqrt{\sqrt{13} + 4}\right)$$
(((x + i*sqrt(4 - sqrt(13)))*(x - i*sqrt(4 - sqrt(13))))*(x + i*sqrt(4 + sqrt(13))))*(x - i*sqrt(4 + sqrt(13)))
The perfect square
Let's highlight the perfect square of the square three-member
$$\left(- y^{4} - 8 y^{2}\right) - 3$$
To do this, let's use the formula
$$a y^{4} + b y^{2} + c = a \left(m + y^{2}\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = -1$$
$$b = -8$$
$$c = -3$$
Then
$$m = 4$$
$$n = 13$$
So,
$$13 - \left(y^{2} + 4\right)^{2}$$
Numerical answer [src]
-3.0 - y^4 - 8.0*y^2
-3.0 - y^4 - 8.0*y^2
Combining rational expressions [src]
      2 /      2\
-3 + y *\-8 - y /
$$y^{2} \left(- y^{2} - 8\right) - 3$$
-3 + y^2*(-8 - y^2)
Assemble expression [src]
      4      2
-3 - y  - 8*y 
$$- y^{4} - 8 y^{2} - 3$$
-3 - y^4 - 8*y^2
Trigonometric part [src]
      4      2
-3 - y  - 8*y 
$$- y^{4} - 8 y^{2} - 3$$
-3 - y^4 - 8*y^2
Rational denominator [src]
      4      2
-3 - y  - 8*y 
$$- y^{4} - 8 y^{2} - 3$$
-3 - y^4 - 8*y^2
Common denominator [src]
      4      2
-3 - y  - 8*y 
$$- y^{4} - 8 y^{2} - 3$$
-3 - y^4 - 8*y^2
Powers [src]
      4      2
-3 - y  - 8*y 
$$- y^{4} - 8 y^{2} - 3$$
-3 - y^4 - 8*y^2
Combinatorics [src]
      4      2
-3 - y  - 8*y 
$$- y^{4} - 8 y^{2} - 3$$
-3 - y^4 - 8*y^2