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How do you (3*y^2-12)/(2*y^2-15*y+18) in partial fractions?

An expression to simplify:

The solution

You have entered [src]
      2         
   3*y  - 12    
----------------
   2            
2*y  - 15*y + 18
$$\frac{3 y^{2} - 12}{\left(2 y^{2} - 15 y\right) + 18}$$
(3*y^2 - 12)/(2*y^2 - 15*y + 18)
General simplification [src]
    /      2\   
  3*\-4 + y /   
----------------
               2
18 - 15*y + 2*y 
$$\frac{3 \left(y^{2} - 4\right)}{2 y^{2} - 15 y + 18}$$
3*(-4 + y^2)/(18 - 15*y + 2*y^2)
Fraction decomposition [src]
3/2 + 7/(6*(-3 + 2*y)) + 32/(3*(-6 + y))
$$\frac{3}{2} + \frac{7}{6 \left(2 y - 3\right)} + \frac{32}{3 \left(y - 6\right)}$$
3        7             32    
- + ------------ + ----------
2   6*(-3 + 2*y)   3*(-6 + y)
Numerical answer [src]
(-12.0 + 3.0*y^2)/(18.0 + 2.0*y^2 - 15.0*y)
(-12.0 + 3.0*y^2)/(18.0 + 2.0*y^2 - 15.0*y)
Rational denominator [src]
            2   
   -12 + 3*y    
----------------
               2
18 - 15*y + 2*y 
$$\frac{3 y^{2} - 12}{2 y^{2} - 15 y + 18}$$
(-12 + 3*y^2)/(18 - 15*y + 2*y^2)
Assemble expression [src]
            2   
   -12 + 3*y    
----------------
               2
18 - 15*y + 2*y 
$$\frac{3 y^{2} - 12}{2 y^{2} - 15 y + 18}$$
(-12 + 3*y^2)/(18 - 15*y + 2*y^2)
Trigonometric part [src]
            2   
   -12 + 3*y    
----------------
               2
18 - 15*y + 2*y 
$$\frac{3 y^{2} - 12}{2 y^{2} - 15 y + 18}$$
(-12 + 3*y^2)/(18 - 15*y + 2*y^2)
Common denominator [src]
3      -78 + 45*y   
- + ----------------
2                  2
    36 - 30*y + 4*y 
$$\frac{45 y - 78}{4 y^{2} - 30 y + 36} + \frac{3}{2}$$
3/2 + (-78 + 45*y)/(36 - 30*y + 4*y^2)
Powers [src]
            2   
   -12 + 3*y    
----------------
               2
18 - 15*y + 2*y 
$$\frac{3 y^{2} - 12}{2 y^{2} - 15 y + 18}$$
(-12 + 3*y^2)/(18 - 15*y + 2*y^2)
Combining rational expressions [src]
     /      2\    
   3*\-4 + y /    
------------------
18 + y*(-15 + 2*y)
$$\frac{3 \left(y^{2} - 4\right)}{y \left(2 y - 15\right) + 18}$$
3*(-4 + y^2)/(18 + y*(-15 + 2*y))
Combinatorics [src]
 3*(-2 + y)*(2 + y)
-------------------
(-6 + y)*(-3 + 2*y)
$$\frac{3 \left(y - 2\right) \left(y + 2\right)}{\left(y - 6\right) \left(2 y - 3\right)}$$
3*(-2 + y)*(2 + y)/((-6 + y)*(-3 + 2*y))