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How do you x/(x^2+2*x-3) in partial fractions?

An expression to simplify:

The solution

You have entered [src]
     x      
------------
 2          
x  + 2*x - 3
$$\frac{x}{\left(x^{2} + 2 x\right) - 3}$$
x/(x^2 + 2*x - 3)
General simplification [src]
      x      
-------------
      2      
-3 + x  + 2*x
$$\frac{x}{x^{2} + 2 x - 3}$$
x/(-3 + x^2 + 2*x)
Fraction decomposition [src]
1/(4*(-1 + x)) + 3/(4*(3 + x))
$$\frac{3}{4 \left(x + 3\right)} + \frac{1}{4 \left(x - 1\right)}$$
    1            3    
---------- + ---------
4*(-1 + x)   4*(3 + x)
Numerical answer [src]
x/(-3.0 + x^2 + 2.0*x)
x/(-3.0 + x^2 + 2.0*x)
Assemble expression [src]
      x      
-------------
      2      
-3 + x  + 2*x
$$\frac{x}{x^{2} + 2 x - 3}$$
x/(-3 + x^2 + 2*x)
Combinatorics [src]
       x        
----------------
(-1 + x)*(3 + x)
$$\frac{x}{\left(x - 1\right) \left(x + 3\right)}$$
x/((-1 + x)*(3 + x))
Powers [src]
      x      
-------------
      2      
-3 + x  + 2*x
$$\frac{x}{x^{2} + 2 x - 3}$$
x/(-3 + x^2 + 2*x)
Trigonometric part [src]
      x      
-------------
      2      
-3 + x  + 2*x
$$\frac{x}{x^{2} + 2 x - 3}$$
x/(-3 + x^2 + 2*x)
Rational denominator [src]
      x      
-------------
      2      
-3 + x  + 2*x
$$\frac{x}{x^{2} + 2 x - 3}$$
x/(-3 + x^2 + 2*x)
Common denominator [src]
      x      
-------------
      2      
-3 + x  + 2*x
$$\frac{x}{x^{2} + 2 x - 3}$$
x/(-3 + x^2 + 2*x)
Combining rational expressions [src]
      x       
--------------
-3 + x*(2 + x)
$$\frac{x}{x \left(x + 2\right) - 3}$$
x/(-3 + x*(2 + x))