Mister Exam
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-
How to use it?
- Graphing y =:
- 1/3x^3-5/2x^2+6x
- x/(2x+1)
- 2x^3-3x^2-12x+1
- x^2/(x-1)^2
- Integral of d{x}:
-
x/(x^2+2*x-3)
- How do you in partial fractions?:
- x/(x^2+2*x-3)
-
Identical expressions
- x/(x^ two + two *x- three)
- x divide by (x squared plus 2 multiply by x minus 3)
- x divide by (x to the power of two plus two multiply by x minus three)
- x/(x2+2*x-3)
- x/x2+2*x-3
- x/(x²+2*x-3)
- x/(x to the power of 2+2*x-3)
- x/(x^2+2x-3)
- x/(x2+2x-3)
- x/x2+2x-3
- x/x^2+2x-3
- x divide by (x^2+2*x-3)
-
Similar expressions
- x/(x^2+2*x+3)
- x/(x^2-2*x-3)
Graphing y = x/(x^2+2*x-3)
The solution
You have entered
[src]
x
f(x) = ------------
2
x + 2*x - 3
$$f{\left(x \right)} = \frac{x}{x^{2} + 2 x - 3}$$
f = x/(x^2 + 2*x - 1*3)
The graph of the function
The domain of the function
The points at which the function is not precisely defined:
$$x_{1} = -3$$
$$x_{2} = 1$$
$$x_{1} = -3$$
$$x_{2} = 1$$
The points of intersection with the X-axis coordinate
Graph of the function intersects the axis X at f = 0
so we need to solve the equation:
$$\frac{x}{x^{2} + 2 x - 3} = 0$$
Solve this equation
The points of intersection with the axis X:
Analytical solution
$$x_{1} = 0$$
Numerical solution
$$x_{1} = 0$$
so we need to solve the equation:
$$\frac{x}{x^{2} + 2 x - 3} = 0$$
Solve this equation
The points of intersection with the axis X:
Analytical solution
$$x_{1} = 0$$
Numerical solution
$$x_{1} = 0$$
Extrema of the function
In order to find the extrema, we need to solve the equation
$$\frac{d}{d x} f{\left(x \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x} f{\left(x \right)} = $$
the first derivative
$$\frac{x \left(- 2 x - 2\right)}{\left(x^{2} + 2 x - 3\right)^{2}} + \frac{1}{x^{2} + 2 x - 3} = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
$$\frac{d}{d x} f{\left(x \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x} f{\left(x \right)} = $$
the first derivative
$$\frac{x \left(- 2 x - 2\right)}{\left(x^{2} + 2 x - 3\right)^{2}} + \frac{1}{x^{2} + 2 x - 3} = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
Inflection points
Let's find the inflection points, we'll need to solve the equation for this
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = $$
the second derivative
$$\frac{2 \left(x \left(\frac{4 \left(x + 1\right)^{2}}{x^{2} + 2 x - 3} - 1\right) - 2 x - 2\right)}{\left(x^{2} + 2 x - 3\right)^{2}} = 0$$
Solve this equation
The roots of this equation
$$x_{1} = - 3^{\frac{2}{3}} + \sqrt[3]{3}$$
You also need to calculate the limits of y '' for arguments seeking to indeterminate points of a function:
Points where there is an indetermination:
$$x_{1} = -3$$
$$x_{2} = 1$$
$$\lim_{x \to -3^-}\left(\frac{2 \left(x \left(\frac{4 \left(x + 1\right)^{2}}{x^{2} + 2 x - 3} - 1\right) - 2 x - 2\right)}{\left(x^{2} + 2 x - 3\right)^{2}}\right) = -\infty$$
Let's take the limit
$$\lim_{x \to -3^+}\left(\frac{2 \left(x \left(\frac{4 \left(x + 1\right)^{2}}{x^{2} + 2 x - 3} - 1\right) - 2 x - 2\right)}{\left(x^{2} + 2 x - 3\right)^{2}}\right) = \infty$$
Let's take the limit
- the limits are not equal, so
$$x_{1} = -3$$
- is an inflection point
$$\lim_{x \to 1^-}\left(\frac{2 \left(x \left(\frac{4 \left(x + 1\right)^{2}}{x^{2} + 2 x - 3} - 1\right) - 2 x - 2\right)}{\left(x^{2} + 2 x - 3\right)^{2}}\right) = -\infty$$
Let's take the limit
$$\lim_{x \to 1^+}\left(\frac{2 \left(x \left(\frac{4 \left(x + 1\right)^{2}}{x^{2} + 2 x - 3} - 1\right) - 2 x - 2\right)}{\left(x^{2} + 2 x - 3\right)^{2}}\right) = \infty$$
Let's take the limit
- the limits are not equal, so
$$x_{2} = 1$$
- is an inflection point
Сonvexity and concavity intervals:
Let’s find the intervals where the function is convex or concave, for this look at the behaviour of the function at the inflection points:
Concave at the intervals
$$\left(-\infty, - 3^{\frac{2}{3}} + \sqrt[3]{3}\right]$$
Convex at the intervals
$$\left[- 3^{\frac{2}{3}} + \sqrt[3]{3}, \infty\right)$$
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = $$
the second derivative
$$\frac{2 \left(x \left(\frac{4 \left(x + 1\right)^{2}}{x^{2} + 2 x - 3} - 1\right) - 2 x - 2\right)}{\left(x^{2} + 2 x - 3\right)^{2}} = 0$$
Solve this equation
The roots of this equation
$$x_{1} = - 3^{\frac{2}{3}} + \sqrt[3]{3}$$
You also need to calculate the limits of y '' for arguments seeking to indeterminate points of a function:
Points where there is an indetermination:
$$x_{1} = -3$$
$$x_{2} = 1$$
$$\lim_{x \to -3^-}\left(\frac{2 \left(x \left(\frac{4 \left(x + 1\right)^{2}}{x^{2} + 2 x - 3} - 1\right) - 2 x - 2\right)}{\left(x^{2} + 2 x - 3\right)^{2}}\right) = -\infty$$
Let's take the limit
$$\lim_{x \to -3^+}\left(\frac{2 \left(x \left(\frac{4 \left(x + 1\right)^{2}}{x^{2} + 2 x - 3} - 1\right) - 2 x - 2\right)}{\left(x^{2} + 2 x - 3\right)^{2}}\right) = \infty$$
Let's take the limit
- the limits are not equal, so
$$x_{1} = -3$$
- is an inflection point
$$\lim_{x \to 1^-}\left(\frac{2 \left(x \left(\frac{4 \left(x + 1\right)^{2}}{x^{2} + 2 x - 3} - 1\right) - 2 x - 2\right)}{\left(x^{2} + 2 x - 3\right)^{2}}\right) = -\infty$$
Let's take the limit
$$\lim_{x \to 1^+}\left(\frac{2 \left(x \left(\frac{4 \left(x + 1\right)^{2}}{x^{2} + 2 x - 3} - 1\right) - 2 x - 2\right)}{\left(x^{2} + 2 x - 3\right)^{2}}\right) = \infty$$
Let's take the limit
- the limits are not equal, so
$$x_{2} = 1$$
- is an inflection point
Сonvexity and concavity intervals:
Let’s find the intervals where the function is convex or concave, for this look at the behaviour of the function at the inflection points:
Concave at the intervals
$$\left(-\infty, - 3^{\frac{2}{3}} + \sqrt[3]{3}\right]$$
Convex at the intervals
$$\left[- 3^{\frac{2}{3}} + \sqrt[3]{3}, \infty\right)$$
Vertical asymptotes
Have:
$$x_{1} = -3$$
$$x_{2} = 1$$
$$x_{1} = -3$$
$$x_{2} = 1$$
Horizontal asymptotes
Let’s find horizontal asymptotes with help of the limits of this function at x->+oo and x->-oo
$$\lim_{x \to -\infty}\left(\frac{x}{x^{2} + 2 x - 3}\right) = 0$$
Let's take the limit
so,
equation of the horizontal asymptote on the left:
$$y = 0$$
$$\lim_{x \to \infty}\left(\frac{x}{x^{2} + 2 x - 3}\right) = 0$$
Let's take the limit
so,
equation of the horizontal asymptote on the right:
$$y = 0$$
$$\lim_{x \to -\infty}\left(\frac{x}{x^{2} + 2 x - 3}\right) = 0$$
Let's take the limit
so,
equation of the horizontal asymptote on the left:
$$y = 0$$
$$\lim_{x \to \infty}\left(\frac{x}{x^{2} + 2 x - 3}\right) = 0$$
Let's take the limit
so,
equation of the horizontal asymptote on the right:
$$y = 0$$
Inclined asymptotes
Inclined asymptote can be found by calculating the limit of x/(x^2 + 2*x - 1*3), divided by x at x->+oo and x ->-oo
$$\lim_{x \to -\infty} \frac{1}{x^{2} + 2 x - 3} = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the right
$$\lim_{x \to \infty} \frac{1}{x^{2} + 2 x - 3} = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the left
$$\lim_{x \to -\infty} \frac{1}{x^{2} + 2 x - 3} = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the right
$$\lim_{x \to \infty} \frac{1}{x^{2} + 2 x - 3} = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the left
Even and odd functions
Let's check, whether the function even or odd by using relations f = f(-x) и f = -f(-x).
So, check:
$$\frac{x}{x^{2} + 2 x - 3} = - \frac{x}{x^{2} - 2 x - 3}$$
- No
$$\frac{x}{x^{2} + 2 x - 3} = \frac{x}{x^{2} - 2 x - 3}$$
- No
so, the function
not is
neither even, nor odd
So, check:
$$\frac{x}{x^{2} + 2 x - 3} = - \frac{x}{x^{2} - 2 x - 3}$$
- No
$$\frac{x}{x^{2} + 2 x - 3} = \frac{x}{x^{2} - 2 x - 3}$$
- No
so, the function
not is
neither even, nor odd
The graph