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How to use it?
How do you in partial fractions?
:
((3*c+1)/(c-1)+c)/(c+1)
z/(z+9)^2-z/(z^2-81)
((z^2-z)/(z^2-9))^-1/(z^2-3*z)/(z-1)
((z)-((7*z)/(z+3)))*((z+3)/(z-4))
Factor polynomial
:
x^6-y^6
x^3+x-2
x^4+x^2+1
x^3+x^2+x+1
Least common denominator
:
x^2*log(x)/2-x^2/4
sqrt(4/x+1)*x+2*log(sqrt(4/x+1)+1)-2*log(sqrt(4/x+1)-1)
atan(tan(f)*sqrt(a^2-1)/a)/sqrt(a^2-1)
(a/5+a/2)*a^2/6
Factor squared
:
-y^4+y^2-4
x^2+3*y*x+2*y^2
y^4-y^2-2
-y^4+y^2-3
Graphing y =
:
x/(x^2+1)
Derivative of
:
x/(x^2+1)
Integral of d{x}
:
x/(x^2+1)
Identical expressions
x/(x^ two + one)
x divide by (x squared plus 1)
x divide by (x to the power of two plus one)
x/(x2+1)
x/x2+1
x/(x²+1)
x/(x to the power of 2+1)
x/x^2+1
x divide by (x^2+1)
Similar expressions
x/(x^2-1)
Expression simplification
/
Fraction Decomposition into the simple
/
x/(x^2+1)
How do you x/(x^2+1) in partial fractions?
An expression to simplify:
Decompose fraction
The solution
You have entered
[src]
x ------ 2 x + 1
$$\frac{x}{x^{2} + 1}$$
x/(x^2 + 1)
Fraction decomposition
[src]
x/(1 + x^2)
$$\frac{x}{x^{2} + 1}$$
x ------ 2 1 + x
Numerical answer
[src]
x/(1.0 + x^2)
x/(1.0 + x^2)