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How to use it?
How do you in partial fractions?
:
((9*b)/(a-b))*((a^2-a*b)/(54*b))
1/(1+x^2/3)
x/(x^2+1)
(x-1)*(1/(2*(x-1))-(x+1)/(2*(x-1)^2))/(x+1)
Factor polynomial
:
x^3+6*x^2-x-6
x^3-x
x^4+x^2+1
r^2-r-r*b+b^2
Least common denominator
:
(c*(v/k+1)+t)/((n+k)*(v/k+1)-k)
(pi*a^2+pi/4)/(pi*a^2+pi/2)
(-cos(x)^5)/5+2*cos(x)^3/3-cos(x)
atan(tan(f)*sqrt(a^2-1)/a)/sqrt(a^2-1)
Factor squared
:
x^2+3*y*x+2*y^2
y^4+y^2+6
y^2-4*y-3
x^2+x-4
Graphing y =
:
x/(x^2+1)
Derivative of
:
x/(x^2+1)
Integral of d{x}
:
x/(x^2+1)
Identical expressions
x/(x^ two + one)
x divide by (x squared plus 1)
x divide by (x to the power of two plus one)
x/(x2+1)
x/x2+1
x/(x²+1)
x/(x to the power of 2+1)
x/x^2+1
x divide by (x^2+1)
Similar expressions
x/(x^2-1)
Expression simplification
/
Fraction Decomposition into the simple
/
x/(x^2+1)
How do you x/(x^2+1) in partial fractions?
An expression to simplify:
Decompose fraction
The solution
You have entered
[src]
x ------ 2 x + 1
$$\frac{x}{x^{2} + 1}$$
x/(x^2 + 1)
Fraction decomposition
[src]
x/(1 + x^2)
$$\frac{x}{x^{2} + 1}$$
x ------ 2 1 + x
Numerical answer
[src]
x/(1.0 + x^2)
x/(1.0 + x^2)