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How to use it?
How do you in partial fractions?
:
x/(x^2+1)
(2x+3)/(x^2-9)
(z-3)/(z+3)*(z+(z^2)/(3-z))
(x^2+3*x-4)/(x+4)
Factor polynomial
:
t^4+1
c^2+c^2
m^2-n^2
x^2+x+1
Least common denominator
:
(z+z/q)*(z-z/q)
((x+8)/x^(2/3)-2*x^(1/3)+4)-((x-8)/x^(1/3)+4)
factorial(s)/factorial(7)/factorial(s-7)/factorial(factorial(2*s))
((z+p)/(2*(z-p)))-((z-p)/(2*(z+p)))-((p)/(z-p))
Factor squared
:
y^4-y^2+3
x^2-x-4
-y^4+y^2-5
-y^4-y^2+1
Graphing y =
:
x/(x^2+1)
Derivative of
:
x/(x^2+1)
Integral of d{x}
:
x/(x^2+1)
Identical expressions
x/(x^ two + one)
x divide by (x squared plus 1)
x divide by (x to the power of two plus one)
x/(x2+1)
x/x2+1
x/(x²+1)
x/(x to the power of 2+1)
x/x^2+1
x divide by (x^2+1)
Similar expressions
x/(x^2-1)
Expression simplification
/
Fraction Decomposition into the simple
/
x/(x^2+1)
How do you x/(x^2+1) in partial fractions?
An expression to simplify:
Decompose fraction
The solution
You have entered
[src]
x ------ 2 x + 1
$$\frac{x}{x^{2} + 1}$$
x/(x^2 + 1)
Fraction decomposition
[src]
x/(1 + x^2)
$$\frac{x}{x^{2} + 1}$$
x ------ 2 1 + x
Numerical answer
[src]
x/(1.0 + x^2)
x/(1.0 + x^2)