Mister Exam

Lang:

How do you (2x+3)/(x^2-9) in partial fractions?

You have entered [src]

2*x + 3
-------
  2    
 x  - 9

$$\frac{2 x + 3}{x^{2} - 9}$$

(2*x + 3)/(x^2 - 9)

Fraction decomposition [src]

1/(2*(3 + x)) + 3/(2*(-3 + x))

$$\frac{1}{2 \left(x + 3\right)} + \frac{3}{2 \left(x - 3\right)}$$

    1           3     
--------- + ----------
2*(3 + x)   2*(-3 + x)

Combinatorics [src]

    3 + 2*x     
----------------
(-3 + x)*(3 + x)

$$\frac{2 x + 3}{\left(x - 3\right) \left(x + 3\right)}$$

(3 + 2*x)/((-3 + x)*(3 + x))

Numerical answer [src]

(3.0 + 2.0*x)/(-9.0 + x^2)

(3.0 + 2.0*x)/(-9.0 + x^2)