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How do you a*(25a^2-81)*(1/(5a+9)-1/(5a-9)) in partial fractions?

An expression to simplify:

The solution

You have entered [src]
  /    2     \ /   1         1   \
a*\25*a  - 81/*|------- - -------|
               \5*a + 9   5*a - 9/
$$a \left(25 a^{2} - 81\right) \left(\frac{1}{5 a + 9} - \frac{1}{5 a - 9}\right)$$
(a*(25*a^2 - 81))*(1/(5*a + 9) - 1/(5*a - 9))
General simplification [src]
-18*a
$$- 18 a$$
-18*a
Fraction decomposition [src]
-18*a
$$- 18 a$$
-18*a
Numerical answer [src]
a*(-81.0 + 25.0*a^2)*(1/(9.0 + 5.0*a) - 1/(-9.0 + 5.0*a))
a*(-81.0 + 25.0*a^2)*(1/(9.0 + 5.0*a) - 1/(-9.0 + 5.0*a))
Common denominator [src]
-18*a
$$- 18 a$$
-18*a
Combining rational expressions [src]
      /          2\ 
-18*a*\-81 + 25*a / 
--------------------
(-9 + 5*a)*(9 + 5*a)
$$- \frac{18 a \left(25 a^{2} - 81\right)}{\left(5 a - 9\right) \left(5 a + 9\right)}$$
-18*a*(-81 + 25*a^2)/((-9 + 5*a)*(9 + 5*a))
Rational denominator [src]
      /          2\ 
-18*a*\-81 + 25*a / 
--------------------
(-9 + 5*a)*(9 + 5*a)
$$- \frac{18 a \left(25 a^{2} - 81\right)}{\left(5 a - 9\right) \left(5 a + 9\right)}$$
-18*a*(-81 + 25*a^2)/((-9 + 5*a)*(9 + 5*a))
Combinatorics [src]
-18*a
$$- 18 a$$
-18*a