Mister Exam
Other calculators
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How to use it?
- Factor squared:
- x^2+x-6
- y^4+y^2-3
- -y^2-4*y+3
- y^4-y^2-8
- Factor polynomial:
- x^2-y^2+x-y
- x^4-5*x^3+6*x^2-10*x+8
- x^4-16
- x^2-81
- Least common denominator:
- sin(k*x+x/2)/2*sin(x/2)+cos(k*x+x)
- ((3*c+1)/(c-1)+c)/(c+1)
- (z*(z^2+6*z+1)-(4*z*(z+1)))/(z-1)^3+z*(z-1)/(z+1)^3
- (x^3+12*x)*(x/(2*(x^3+12*x))+(-12-3*x^2)*(x^2+4)/(4*(x^3+12*x)^2))/(x^2+4)
- How do you in partial fractions?:
- z/(z+4)^2-z/z^2-16
- -x^2/(x-2)^2+2*x/(x-2)
- -1/(3*x^3)
- -2*sqrt(3)/(3*sqrt(1-(2*x-1)^2/3))
- Graphing y =:
- x^2+x-6
- Equation:
- x^2+x-6
- Integral of d{x}:
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x^2+x-6
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Identical expressions
- x^ two +x- six
- x squared plus x minus 6
- x to the power of two plus x minus six
- x2+x-6
- x²+x-6
- x to the power of 2+x-6
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Similar expressions
- x^2+x+6
- x^2-x-6
Factor x^2+x-6 squared
The solution
The perfect square
Let's highlight the perfect square of the square three-member
$$\left(x^{2} + x\right) - 6$$
To do this, let's use the formula
$$a x^{2} + b x + c = a \left(m + x\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = 1$$
$$b = 1$$
$$c = -6$$
Then
$$m = \frac{1}{2}$$
$$n = - \frac{25}{4}$$
So,
$$\left(x + \frac{1}{2}\right)^{2} - \frac{25}{4}$$
$$\left(x^{2} + x\right) - 6$$
To do this, let's use the formula
$$a x^{2} + b x + c = a \left(m + x\right)^{2} + n$$
where
$$m = \frac{b}{2 a}$$
$$n = \frac{4 a c - b^{2}}{4 a}$$
In this case
$$a = 1$$
$$b = 1$$
$$c = -6$$
Then
$$m = \frac{1}{2}$$
$$n = - \frac{25}{4}$$
So,
$$\left(x + \frac{1}{2}\right)^{2} - \frac{25}{4}$$