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Limit of the function
:
Limit of (1-4*x)^(1/x)
Limit of (-16+x^2+6*x)/(-2-5*x+3*x^2)
Limit of (1+x)^(2/3)-(-1+x)^(2/3)
Limit of 1/3+x/3
Derivative of
:
(x^2)^(1/3)
Graphing y =
:
(x^2)^(1/3)
Integral of d{x}
:
(x^2)^(1/3)
Identical expressions
(x^ two)^(one / three)
(x squared ) to the power of (1 divide by 3)
(x to the power of two) to the power of (one divide by three)
(x2)(1/3)
x21/3
(x²)^(1/3)
(x to the power of 2) to the power of (1/3)
x^2^1/3
(x^2)^(1 divide by 3)
Similar expressions
x/(1-x^2)^(1/3)
(x+x^3+9*x^2)^(1/3)-x
(-2+sqrt(x))/(-16+x^2)^(1/3)
Limit of the function
/
(x^2)^(1/3)
Limit of the function (x^2)^(1/3)
at
→
Calculate the limit!
v
For end points:
---------
From the left (x0-)
From the right (x0+)
The graph:
from
to
Piecewise:
{
enter the piecewise function here
The solution
You have entered
[src]
____ 3 / 2 lim \/ x x->oo
$$\lim_{x \to \infty} \sqrt[3]{x^{2}}$$
Limit((x^2)^(1/3), x, oo, dir='-')
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
Plot the graph
Other limits x→0, -oo, +oo, 1
$$\lim_{x \to \infty} \sqrt[3]{x^{2}} = \infty$$
$$\lim_{x \to 0^-} \sqrt[3]{x^{2}} = 0$$
More at x→0 from the left
$$\lim_{x \to 0^+} \sqrt[3]{x^{2}} = 0$$
More at x→0 from the right
$$\lim_{x \to 1^-} \sqrt[3]{x^{2}} = 1$$
More at x→1 from the left
$$\lim_{x \to 1^+} \sqrt[3]{x^{2}} = 1$$
More at x→1 from the right
$$\lim_{x \to -\infty} \sqrt[3]{x^{2}} = \infty$$
More at x→-oo
Rapid solution
[src]
oo
$$\infty$$
Expand and simplify
The graph