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x+3*x^2

Limit of the function x+3*x^2

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     /       2\
 lim \x + 3*x /
x->oo          
$$\lim_{x \to \infty}\left(3 x^{2} + x\right)$$
Limit(x + 3*x^2, x, oo, dir='-')
Detail solution
Let's take the limit
$$\lim_{x \to \infty}\left(3 x^{2} + x\right)$$
Let's divide numerator and denominator by x^2:
$$\lim_{x \to \infty}\left(3 x^{2} + x\right)$$ =
$$\lim_{x \to \infty}\left(\frac{3 + \frac{1}{x}}{\frac{1}{x^{2}}}\right)$$
Do Replacement
$$u = \frac{1}{x}$$
then
$$\lim_{x \to \infty}\left(\frac{3 + \frac{1}{x}}{\frac{1}{x^{2}}}\right) = \lim_{u \to 0^+}\left(\frac{u + 3}{u^{2}}\right)$$
=
$$\frac{3}{0} = \infty$$

The final answer:
$$\lim_{x \to \infty}\left(3 x^{2} + x\right) = \infty$$
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
Rapid solution [src]
oo
$$\infty$$
Other limits x→0, -oo, +oo, 1
$$\lim_{x \to \infty}\left(3 x^{2} + x\right) = \infty$$
$$\lim_{x \to 0^-}\left(3 x^{2} + x\right) = 0$$
More at x→0 from the left
$$\lim_{x \to 0^+}\left(3 x^{2} + x\right) = 0$$
More at x→0 from the right
$$\lim_{x \to 1^-}\left(3 x^{2} + x\right) = 4$$
More at x→1 from the left
$$\lim_{x \to 1^+}\left(3 x^{2} + x\right) = 4$$
More at x→1 from the right
$$\lim_{x \to -\infty}\left(3 x^{2} + x\right) = \infty$$
More at x→-oo
The graph
Limit of the function x+3*x^2