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Limit of the function
:
Limit of x^2/(3+x^3-4*x)
Limit of (-12+x^2+4*x)/(-4+x^2)
Limit of (-10+x^2+3*x)/(16+x^2-10*x)
Limit of (6+x^2+2*x)/(-1+3*x^2+7*x)
Graphing y =
:
e^(-n)
Sum of series
:
e^(-n)
Integral of d{x}
:
e^(-n)
Identical expressions
e^(-n)
e to the power of ( minus n)
e(-n)
e-n
e^-n
Similar expressions
e^(n)
Limit of the function
/
e^(-n)
Limit of the function e^(-n)
at
→
Calculate the limit!
v
For end points:
---------
From the left (x0-)
From the right (x0+)
The graph:
from
to
Piecewise:
{
enter the piecewise function here
The solution
You have entered
[src]
-n lim E n->oo
lim
n
→
∞
e
−
n
\lim_{n \to \infty} e^{- n}
n
→
∞
lim
e
−
n
Limit(E^(-n), n, oo, dir='-')
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
0
2
4
6
8
-8
-6
-4
-2
-10
10
0
20000
Plot the graph
Other limits n→0, -oo, +oo, 1
lim
n
→
∞
e
−
n
=
0
\lim_{n \to \infty} e^{- n} = 0
n
→
∞
lim
e
−
n
=
0
lim
n
→
0
−
e
−
n
=
1
\lim_{n \to 0^-} e^{- n} = 1
n
→
0
−
lim
e
−
n
=
1
More at n→0 from the left
lim
n
→
0
+
e
−
n
=
1
\lim_{n \to 0^+} e^{- n} = 1
n
→
0
+
lim
e
−
n
=
1
More at n→0 from the right
lim
n
→
1
−
e
−
n
=
e
−
1
\lim_{n \to 1^-} e^{- n} = e^{-1}
n
→
1
−
lim
e
−
n
=
e
−
1
More at n→1 from the left
lim
n
→
1
+
e
−
n
=
e
−
1
\lim_{n \to 1^+} e^{- n} = e^{-1}
n
→
1
+
lim
e
−
n
=
e
−
1
More at n→1 from the right
lim
n
→
−
∞
e
−
n
=
∞
\lim_{n \to -\infty} e^{- n} = \infty
n
→
−
∞
lim
e
−
n
=
∞
More at n→-oo
Rapid solution
[src]
0
0
0
0
Expand and simplify
The graph