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Derivative of:
(x^2+5)/(x+2)
Graphing y =:
(x^2+5)/(x+2)
Identical expressions
(x^ two + five)/(x+ two)
(x squared plus 5) divide by (x plus 2)
(x to the power of two plus five) divide by (x plus two)
(x2+5)/(x+2)
x2+5/x+2
(x²+5)/(x+2)
(x to the power of 2+5)/(x+2)
x^2+5/x+2
(x^2+5) divide by (x+2)
(x^2+5)/(x+2)dx
Similar expressions
(x^2-5)/(x+2)
(x^2+5)/(x-2)

Solving integrals/ (x^2+5)/(x+2)

Integral of (x^2+5)/(x+2) dx

The solution

You have entered [src]

  1          
  /          
 |           
 |   2       
 |  x  + 5   
 |  ------ dx
 |  x + 2    
 |           
/            
0

$$\int\limits_{0}^{1} \frac{x^{2} + 5}{x + 2}\, dx$$

Integral((x^2 + 5)/(x + 2), (x, 0, 1))

Detail solution

There are multiple ways to do this integral.
Method #1
1. Rewrite the integrand:
  
  $\frac{x^{2} + 5}{x + 2} = x - 2 + \frac{9}{x + 2}$
2. Integrate term-by-term:
  1. The integral of $x^{n}$ is $\frac{x^{n + 1}}{n + 1}$ when $n \neq -1$ :
    
    $\int x\, dx = \frac{x^{2}}{2}$
  1. The integral of a constant is the constant times the variable of integration:
    
    $\int \left(-2\right)\, dx = - 2 x$
  1. The integral of a constant times a function is the constant times the integral of the function:
    
    $\int \frac{9}{x + 2}\, dx = 9 \int \frac{1}{x + 2}\, dx$
    1. Let $u = x + 2$ .
      
      Then let $du = dx$ and substitute $du$ :
      
      $\int \frac{1}{u}\, du$
      
      The integral of $\frac{1}{u}$ is $\log{\left(u \right)}$ .
      
      Now substitute $u$ back in:
      
      $\log{\left(x + 2 \right)}$
    So, the result is: $9 \log{\left(x + 2 \right)}$
  The result is: $\frac{x^{2}}{2} - 2 x + 9 \log{\left(x + 2 \right)}$
Method #2
1. Rewrite the integrand:
  
  $\frac{x^{2} + 5}{x + 2} = \frac{x^{2}}{x + 2} + \frac{5}{x + 2}$
2. Integrate term-by-term:
  1. Rewrite the integrand:
    
    $\frac{x^{2}}{x + 2} = x - 2 + \frac{4}{x + 2}$
  2. Integrate term-by-term:
    1. The integral of $x^{n}$ is $\frac{x^{n + 1}}{n + 1}$ when $n \neq -1$ :
      
      $\int x\, dx = \frac{x^{2}}{2}$
    1. The integral of a constant is the constant times the variable of integration:
      
      $\int \left(-2\right)\, dx = - 2 x$
    1. The integral of a constant times a function is the constant times the integral of the function:
      
      $\int \frac{4}{x + 2}\, dx = 4 \int \frac{1}{x + 2}\, dx$
      
      Let $u = x + 2$ .
      
      Then let $du = dx$ and substitute $du$ :
      
      $\int \frac{1}{u}\, du$
      
      The integral of $\frac{1}{u}$ is $\log{\left(u \right)}$ .
      
      Now substitute $u$ back in:
      
      $\log{\left(x + 2 \right)}$
      
      So, the result is: $4 \log{\left(x + 2 \right)}$
    The result is: $\frac{x^{2}}{2} - 2 x + 4 \log{\left(x + 2 \right)}$
  1. The integral of a constant times a function is the constant times the integral of the function:
    
    $\int \frac{5}{x + 2}\, dx = 5 \int \frac{1}{x + 2}\, dx$
    1. Let $u = x + 2$ .
      
      Then let $du = dx$ and substitute $du$ :
      
      $\int \frac{1}{u}\, du$
      
      The integral of $\frac{1}{u}$ is $\log{\left(u \right)}$ .
      
      Now substitute $u$ back in:
      
      $\log{\left(x + 2 \right)}$
    So, the result is: $5 \log{\left(x + 2 \right)}$
  The result is: $\frac{x^{2}}{2} - 2 x + 5 \log{\left(x + 2 \right)} + 4 \log{\left(x + 2 \right)}$
Add the constant of integration:

$\frac{x^{2}}{2} - 2 x + 9 \log{\left(x + 2 \right)}+ \mathrm{constant}$

The answer is:

$\frac{x^{2}}{2} - 2 x + 9 \log{\left(x + 2 \right)}+ \mathrm{constant}$

The answer (Indefinite) [src]

  /                                       
 |                                        
 |  2               2                     
 | x  + 5          x                      
 | ------ dx = C + -- - 2*x + 9*log(2 + x)
 | x + 2           2                      
 |                                        
/

$$\int \frac{x^{2} + 5}{x + 2}\, dx = C + \frac{x^{2}}{2} - 2 x + 9 \log{\left(x + 2 \right)}$$

Simplify

The graph

Plot the graph f(x)

The answer [src]

-3/2 - 9*log(2) + 9*log(3)

$$- 9 \log{\left(2 \right)} - \frac{3}{2} + 9 \log{\left(3 \right)}$$

-3/2 - 9*log(2) + 9*log(3)

$$- 9 \log{\left(2 \right)} - \frac{3}{2} + 9 \log{\left(3 \right)}$$

-3/2 - 9*log(2) + 9*log(3)

Numerical answer [src]

2.14918597297348

2.14918597297348

The graph

Use the examples entering the upper and lower limits of integration.

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Identical expressions

Similar expressions

Integral of (x^2+5)/(x+2) dx

Limits of integration:

The graph:

Piecewise:

The solution

Method #1

Method #2