Integral of (x^2+5)/(x-2) dx
The solution
Detail solution
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There are multiple ways to do this integral.
Method #1
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Rewrite the integrand:
x−2x2+5=x+2+x−29
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Integrate term-by-term:
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The integral of xn is n+1xn+1 when n=−1:
∫xdx=2x2
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The integral of a constant is the constant times the variable of integration:
∫2dx=2x
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The integral of a constant times a function is the constant times the integral of the function:
∫x−29dx=9∫x−21dx
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Let u=x−2.
Then let du=dx and substitute du:
∫u1du
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The integral of u1 is log(u).
Now substitute u back in:
log(x−2)
So, the result is: 9log(x−2)
The result is: 2x2+2x+9log(x−2)
Method #2
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Rewrite the integrand:
x−2x2+5=x−2x2+x−25
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Integrate term-by-term:
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Rewrite the integrand:
x−2x2=x+2+x−24
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Integrate term-by-term:
-
The integral of xn is n+1xn+1 when n=−1:
∫xdx=2x2
-
The integral of a constant is the constant times the variable of integration:
∫2dx=2x
-
The integral of a constant times a function is the constant times the integral of the function:
∫x−24dx=4∫x−21dx
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Let u=x−2.
Then let du=dx and substitute du:
∫u1du
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The integral of u1 is log(u).
Now substitute u back in:
log(x−2)
So, the result is: 4log(x−2)
The result is: 2x2+2x+4log(x−2)
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The integral of a constant times a function is the constant times the integral of the function:
∫x−25dx=5∫x−21dx
-
Let u=x−2.
Then let du=dx and substitute du:
∫u1du
-
The integral of u1 is log(u).
Now substitute u back in:
log(x−2)
So, the result is: 5log(x−2)
The result is: 2x2+2x+5log(x−2)+4log(x−2)
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Add the constant of integration:
2x2+2x+9log(x−2)+constant
The answer is:
2x2+2x+9log(x−2)+constant
The answer (Indefinite)
[src]
/
|
| 2 2
| x + 5 x
| ------ dx = C + -- + 2*x + 9*log(-2 + x)
| x - 2 2
|
/
∫x−2x2+5dx=C+2x2+2x+9log(x−2)
The graph
Use the examples entering the upper and lower limits of integration.