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(x^2-2)^2

Integral of (x^2-2)^2 dx

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The solution

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01(x22)2dx\int\limits_{0}^{1} \left(x^{2} - 2\right)^{2}\, dx
Integral((x^2 - 2)^2, (x, 0, 1))
Detail solution
  1. Rewrite the integrand:

    (x22)2=x44x2+4\left(x^{2} - 2\right)^{2} = x^{4} - 4 x^{2} + 4

  2. Integrate term-by-term:

    1. The integral of xnx^{n} is xn+1n+1\frac{x^{n + 1}}{n + 1} when n1n \neq -1:

      x4dx=x55\int x^{4}\, dx = \frac{x^{5}}{5}

    1. The integral of a constant times a function is the constant times the integral of the function:

      (4x2)dx=4x2dx\int \left(- 4 x^{2}\right)\, dx = - 4 \int x^{2}\, dx

      1. The integral of xnx^{n} is xn+1n+1\frac{x^{n + 1}}{n + 1} when n1n \neq -1:

        x2dx=x33\int x^{2}\, dx = \frac{x^{3}}{3}

      So, the result is: 4x33- \frac{4 x^{3}}{3}

    1. The integral of a constant is the constant times the variable of integration:

      4dx=4x\int 4\, dx = 4 x

    The result is: x554x33+4x\frac{x^{5}}{5} - \frac{4 x^{3}}{3} + 4 x

  3. Now simplify:

    x(3x420x2+60)15\frac{x \left(3 x^{4} - 20 x^{2} + 60\right)}{15}

  4. Add the constant of integration:

    x(3x420x2+60)15+constant\frac{x \left(3 x^{4} - 20 x^{2} + 60\right)}{15}+ \mathrm{constant}


The answer is:

x(3x420x2+60)15+constant\frac{x \left(3 x^{4} - 20 x^{2} + 60\right)}{15}+ \mathrm{constant}

The answer (Indefinite) [src]
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(x22)2dx=C+x554x33+4x\int \left(x^{2} - 2\right)^{2}\, dx = C + \frac{x^{5}}{5} - \frac{4 x^{3}}{3} + 4 x
The graph
0.001.000.100.200.300.400.500.600.700.800.9005
The answer [src]
43
--
15
4315\frac{43}{15}
=
=
43
--
15
4315\frac{43}{15}
43/15
Numerical answer [src]
2.86666666666667
2.86666666666667
The graph
Integral of (x^2-2)^2 dx

    Use the examples entering the upper and lower limits of integration.