Integral of (x^2-2)^2 dx
The solution
Detail solution
-
Rewrite the integrand:
(x2−2)2=x4−4x2+4
-
Integrate term-by-term:
-
The integral of xn is n+1xn+1 when n=−1:
∫x4dx=5x5
-
The integral of a constant times a function is the constant times the integral of the function:
∫(−4x2)dx=−4∫x2dx
-
The integral of xn is n+1xn+1 when n=−1:
∫x2dx=3x3
So, the result is: −34x3
-
The integral of a constant is the constant times the variable of integration:
∫4dx=4x
The result is: 5x5−34x3+4x
-
Now simplify:
15x(3x4−20x2+60)
-
Add the constant of integration:
15x(3x4−20x2+60)+constant
The answer is:
15x(3x4−20x2+60)+constant
The answer (Indefinite)
[src]
/
|
| 2 3 5
| / 2 \ 4*x x
| \x - 2/ dx = C + 4*x - ---- + --
| 3 5
/
∫(x2−2)2dx=C+5x5−34x3+4x
The graph
Use the examples entering the upper and lower limits of integration.