Integral of xsin(4x) dx

The solution

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 |  x*sin(4*x) dx
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$$\int\limits_{0}^{1} x \sin{\left(4 x \right)}\, dx$$

Integral(x*sin(4*x), (x, 0, 1))

Detail solution

Use integration by parts:

$\int \operatorname{u} \operatorname{dv} = \operatorname{u}\operatorname{v} - \int \operatorname{v} \operatorname{du}$

Let $u{\left(x \right)} = x$ and let $\operatorname{dv}{\left(x \right)} = \sin{\left(4 x \right)}$ .

Then $\operatorname{du}{\left(x \right)} = 1$ .

To find $v{\left(x \right)}$ :
1. Let $u = 4 x$ .
  
  Then let $du = 4 dx$ and substitute $\frac{du}{4}$ :
  
  $\int \frac{\sin{\left(u \right)}}{4}\, du$
  1. The integral of a constant times a function is the constant times the integral of the function:
    
    $\int \sin{\left(u \right)}\, du = \frac{\int \sin{\left(u \right)}\, du}{4}$
    1. The integral of sine is negative cosine:
      
      $\int \sin{\left(u \right)}\, du = - \cos{\left(u \right)}$
    So, the result is: $- \frac{\cos{\left(u \right)}}{4}$
  Now substitute $u$ back in:
  
  $- \frac{\cos{\left(4 x \right)}}{4}$
Now evaluate the sub-integral.
The integral of a constant times a function is the constant times the integral of the function:

$\int \left(- \frac{\cos{\left(4 x \right)}}{4}\right)\, dx = - \frac{\int \cos{\left(4 x \right)}\, dx}{4}$
1. Let $u = 4 x$ .
  
  Then let $du = 4 dx$ and substitute $\frac{du}{4}$ :
  
  $\int \frac{\cos{\left(u \right)}}{4}\, du$
  1. The integral of a constant times a function is the constant times the integral of the function:
    
    $\int \cos{\left(u \right)}\, du = \frac{\int \cos{\left(u \right)}\, du}{4}$
    1. The integral of cosine is sine:
      
      $\int \cos{\left(u \right)}\, du = \sin{\left(u \right)}$
    So, the result is: $\frac{\sin{\left(u \right)}}{4}$
  Now substitute $u$ back in:
  
  $\frac{\sin{\left(4 x \right)}}{4}$
So, the result is: $- \frac{\sin{\left(4 x \right)}}{16}$
Add the constant of integration:

$- \frac{x \cos{\left(4 x \right)}}{4} + \frac{\sin{\left(4 x \right)}}{16}+ \mathrm{constant}$

The answer is:

$- \frac{x \cos{\left(4 x \right)}}{4} + \frac{\sin{\left(4 x \right)}}{16}+ \mathrm{constant}$

The answer (Indefinite) [src]

  /                                         
 |                     sin(4*x)   x*cos(4*x)
 | x*sin(4*x) dx = C + -------- - ----------
 |                        16          4     
/

$$\int x \sin{\left(4 x \right)}\, dx = C - \frac{x \cos{\left(4 x \right)}}{4} + \frac{\sin{\left(4 x \right)}}{16}$$

Simplify

The graph

Plot the graph f(x)

The answer [src]

  cos(4)   sin(4)
- ------ + ------
    4        16

$$\frac{\sin{\left(4 \right)}}{16} - \frac{\cos{\left(4 \right)}}{4}$$

  cos(4)   sin(4)
- ------ + ------
    4        16

$$\frac{\sin{\left(4 \right)}}{16} - \frac{\cos{\left(4 \right)}}{4}$$

-cos(4)/4 + sin(4)/16

Numerical answer [src]

0.116110749259157

0.116110749259157

The graph

Use the examples entering the upper and lower limits of integration.

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Integral of xsin(4x) dx

Limits of integration:

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Piecewise:

The solution