Integral of 2xe^(x^2) dx
The solution
Detail solution
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The integral of a constant times a function is the constant times the integral of the function:
∫2xex2dx=2∫xex2dx
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Let u=ex2.
Then let du=2xex2dx and substitute 2du:
∫41du
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The integral of a constant times a function is the constant times the integral of the function:
∫21du=2∫1du
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The integral of a constant is the constant times the variable of integration:
∫1du=u
So, the result is: 2u
Now substitute u back in:
2ex2
So, the result is: ex2
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Add the constant of integration:
ex2+constant
The answer is:
ex2+constant
The answer (Indefinite)
[src]
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| / 2\ / 2\
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| 2*x*e dx = C + e
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The graph
2(2e−21)
=
Use the examples entering the upper and lower limits of integration.