Integral of (2x^2+3)dx dx
The solution
Detail solution
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Integrate term-by-term:
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The integral of a constant times a function is the constant times the integral of the function:
∫2x2dx=2∫x2dx
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The integral of xn is n+1xn+1 when n=−1:
∫x2dx=3x3
So, the result is: 32x3
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The integral of a constant is the constant times the variable of integration:
∫3dx=3x
The result is: 32x3+3x
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Now simplify:
3x(2x2+9)
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Add the constant of integration:
3x(2x2+9)+constant
The answer is:
3x(2x2+9)+constant
The answer (Indefinite)
[src]
/
| 3
| / 2 \ 2*x
| \2*x + 3/ dx = C + 3*x + ----
| 3
/
∫(2x2+3)dx=C+32x3+3x
The graph
Use the examples entering the upper and lower limits of integration.