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Solving integrals/ tan(x^2+1)

Integral of tan(x^2+1) dx

Limits of integration:

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The solution

You have entered [src] 
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∫01tan⁡(x2+1) dx\int\limits_{0}^{1} \tan{\left(x^{2} + 1 \right)}\, dx 
Integral(tan(x^2 + 1), (x, 0, 1))
Detail solution

  1. Rewrite the integrand:

    tan⁡(x2+1)=sin⁡(x2+1)cos⁡(x2+1)\tan{\left(x^{2} + 1 \right)} = \frac{\sin{\left(x^{2} + 1 \right)}}{\cos{\left(x^{2} + 1 \right)}}

  2. Don't know the steps in finding this integral.

    But the integral is

    ∫sin⁡(x2+1)cos⁡(x2+1) dx\int \frac{\sin{\left(x^{2} + 1 \right)}}{\cos{\left(x^{2} + 1 \right)}}\, dx

  3. Now simplify:

    ∫tan⁡(x2+1) dx\int \tan{\left(x^{2} + 1 \right)}\, dx

  4. Add the constant of integration:

    ∫tan⁡(x2+1) dx+constant\int \tan{\left(x^{2} + 1 \right)}\, dx+ \mathrm{constant}

The answer is:

∫tan⁡(x2+1) dx+constant\int \tan{\left(x^{2} + 1 \right)}\, dx+ \mathrm{constant}

The answer (Indefinite) [src] 
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∫tan⁡(x2+1) dx=C+∫sin⁡(x2+1)cos⁡(x2+1) dx\int \tan{\left(x^{2} + 1 \right)}\, dx = C + \int \frac{\sin{\left(x^{2} + 1 \right)}}{\cos{\left(x^{2} + 1 \right)}}\, dx
Simplify
The answer [src] 
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∫01tan⁡(x2+1) dx\int\limits_{0}^{1} \tan{\left(x^{2} + 1 \right)}\, dx 
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= 
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∫01tan⁡(x2+1) dx\int\limits_{0}^{1} \tan{\left(x^{2} + 1 \right)}\, dx
Упростить
Numerical answer [src] 
1.1158721984137
1.1158721984137

    Use the examples entering the upper and lower limits of integration.

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