Integral of tan(x^2+1) dx
The solution
Detail solution
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Rewrite the integrand:
tan(x2+1)=cos(x2+1)sin(x2+1)
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Don't know the steps in finding this integral.
But the integral is
∫cos(x2+1)sin(x2+1)dx
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Now simplify:
∫tan(x2+1)dx
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Add the constant of integration:
∫tan(x2+1)dx+constant
The answer is:
∫tan(x2+1)dx+constant
The answer (Indefinite)
[src]
/
/ |
| | / 2 \
| / 2 \ | sin\x + 1/
| tan\x + 1/ dx = C + | ----------- dx
| | / 2 \
/ | cos\x + 1/
|
/
∫tan(x2+1)dx=C+∫cos(x2+1)sin(x2+1)dx
1
/
|
| / 2\
| tan\1 + x / dx
|
/
0
0∫1tan(x2+1)dx
=
1
/
|
| / 2\
| tan\1 + x / dx
|
/
0
0∫1tan(x2+1)dx
Use the examples entering the upper and lower limits of integration.