Mister Exam
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- Improper integral
- Double Integral
- Triple Integral
- Curvilinear integral
- Derivative Step by Step
- Differential equations Step by Step
- Limits Step by Step
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How to use it?
- Integral of d{x}:
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Integral of sinxcos^5x
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Integral of sin(7x)*cos(3x)
- Integral of sqrt(2-2sinx)
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Integral of cosh^2(x)
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Identical expressions
- sqrt(two -2sinx)
- square root of (2 minus 2 sinus of x)
- square root of (two minus 2 sinus of x)
- √(2-2sinx)
- sqrt2-2sinx
- sqrt(2-2sinx)dx
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Similar expressions
- sqrt(2-2sin(x))
- sqrt(2-2*sin(x))
- sqrt(2+2sinx)
- sqrt2-2sin(x)
- 4*sqrt(2-2sin(x))
Integral of sqrt(2-2sinx) dx
The solution
You have entered
[src]
pi -- 6 / | | ______________ | \/ 2 - 2*sin(x) dx | / 0
$$\int\limits_{0}^{\frac{\pi}{6}} \sqrt{- 2 \sin{\left(x \right)} + 2}\, dx$$
Detail solution
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Rewrite the integrand:
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The integral of a constant times a function is the constant times the integral of the function:
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Don't know the steps in finding this integral.
But the integral is
So, the result is:
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Add the constant of integration:
The answer is:
The answer (Indefinite)
[src]
/ / | | | ______________ ___ | ____________ | \/ 2 - 2*sin(x) dx = C + \/ 2 * | \/ 1 - sin(x) dx | | / /
$$\int {\sqrt{2-2\,\sin x}}{\;dx}$$
The answer
[src]
pi
--
6
/
|
___ | ____________
\/ 2 * | \/ 1 - sin(x) dx
|
/
0
$$\sqrt{2} \int\limits_{0}^{\frac{\pi}{6}} \sqrt{- \sin{\left(x \right)} + 1}\, dx$$
=
=
pi
--
6
/
|
___ | ____________
\/ 2 * | \/ 1 - sin(x) dx
|
/
0
$$\sqrt{2} \int\limits_{0}^{\frac{\pi}{6}} \sqrt{- \sin{\left(x \right)} + 1}\, dx$$
Use the examples entering the upper and lower limits of integration.