Integral of (sinx-cosx)dx dx
The solution
Detail solution
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Integrate term-by-term:
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The integral of sine is negative cosine:
∫sin(x)dx=−cos(x)
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The integral of a constant times a function is the constant times the integral of the function:
∫(−cos(x))dx=−∫cos(x)dx
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The integral of cosine is sine:
∫cos(x)dx=sin(x)
So, the result is: −sin(x)
The result is: −sin(x)−cos(x)
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Now simplify:
−2sin(x+4π)
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Add the constant of integration:
−2sin(x+4π)+constant
The answer is:
−2sin(x+4π)+constant
The answer (Indefinite)
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| (sin(x) - cos(x)) dx = C - cos(x) - sin(x)
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∫(sin(x)−cos(x))dx=C−sin(x)−cos(x)
The graph
−sin(1)−cos(1)+1
=
−sin(1)−cos(1)+1
Use the examples entering the upper and lower limits of integration.