Integral of (sinx+cosx)dx dx
The solution
Detail solution
-
Integrate term-by-term:
-
The integral of sine is negative cosine:
∫sin(x)dx=−cos(x)
-
The integral of cosine is sine:
∫cos(x)dx=sin(x)
The result is: sin(x)−cos(x)
-
Now simplify:
−2cos(x+4π)
-
Add the constant of integration:
−2cos(x+4π)+constant
The answer is:
−2cos(x+4π)+constant
The answer (Indefinite)
[src]
/
|
| (sin(x) + cos(x)) dx = C - cos(x) + sin(x)
|
/
∫(sin(x)+cos(x))dx=C+sin(x)−cos(x)
The graph
−cos(1)+sin(1)+1
=
−cos(1)+sin(1)+1
Use the examples entering the upper and lower limits of integration.