Integral of (-1)/(x+1) dx
The solution
Detail solution
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The integral of a constant times a function is the constant times the integral of the function:
∫(−x+11)dx=−∫x+11dx
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Let u=x+1.
Then let du=dx and substitute du:
∫u1du
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The integral of u1 is log(u).
Now substitute u back in:
log(x+1)
So, the result is: −log(x+1)
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Now simplify:
−log(x+1)
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Add the constant of integration:
−log(x+1)+constant
The answer is:
−log(x+1)+constant
The answer (Indefinite)
[src]
/
|
| -1
| ----- dx = C - log(x + 1)
| x + 1
|
/
−log(x+1)
The graph
=
−log(2)
Use the examples entering the upper and lower limits of integration.