Integral of sin(x)/(1-cos^2(x)) dx
The solution
Detail solution
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Rewrite the integrand:
1−cos2(x)sin(x)=−cos2(x)−1sin(x)
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The integral of a constant times a function is the constant times the integral of the function:
∫(−cos2(x)−1sin(x))dx=−∫cos2(x)−1sin(x)dx
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Don't know the steps in finding this integral.
But the integral is
−2log(cos(x)−1)+2log(cos(x)+1)
So, the result is: 2log(cos(x)−1)−2log(cos(x)+1)
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Add the constant of integration:
2log(cos(x)−1)−2log(cos(x)+1)+constant
The answer is:
2log(cos(x)−1)−2log(cos(x)+1)+constant
The answer (Indefinite)
[src]
/
|
| sin(x) log(-1 + cos(x)) log(1 + cos(x))
| ----------- dx = C + ---------------- - ---------------
| 2 2 2
| 1 - cos (x)
|
/
∫1−cos2(x)sin(x)dx=C+2log(cos(x)−1)−2log(cos(x)+1)
The graph
∞+2iπ
=
∞+2iπ
Use the examples entering the upper and lower limits of integration.