Integral of -xsinx dx
The solution
Detail solution
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Use integration by parts:
∫udv=uv−∫vdu
Let u(x)=−x and let dv(x)=sin(x).
Then du(x)=−1.
To find v(x):
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The integral of sine is negative cosine:
∫sin(x)dx=−cos(x)
Now evaluate the sub-integral.
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The integral of cosine is sine:
∫cos(x)dx=sin(x)
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Add the constant of integration:
xcos(x)−sin(x)+constant
The answer is:
xcos(x)−sin(x)+constant
The answer (Indefinite)
[src]
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| -x*sin(x) dx = C - sin(x) + x*cos(x)
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∫−xsin(x)dx=C+xcos(x)−sin(x)
The graph
−sin(1)+cos(1)
=
−sin(1)+cos(1)
Use the examples entering the upper and lower limits of integration.