Integral of -cos(2x) dx

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 |  -cos(2*x) dx
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\int\limits_{0}^{1} \left(- \cos{\left(2 x \right)}\right)\, dx

Integral(-cos(2*x), (x, 0, 1))

Detail solution

The integral of a constant times a function is the constant times the integral of the function:

$\int \left(- \cos{\left(2 x \right)}\right)\, dx = - \int \cos{\left(2 x \right)}\, dx$
1. Let $u = 2 x$ .
  
  Then let $du = 2 dx$ and substitute $\frac{du}{2}$ :
  
  $\int \frac{\cos{\left(u \right)}}{2}\, du$
  1. The integral of a constant times a function is the constant times the integral of the function:
    
    $\int \cos{\left(u \right)}\, du = \frac{\int \cos{\left(u \right)}\, du}{2}$
    1. The integral of cosine is sine:
      
      $\int \cos{\left(u \right)}\, du = \sin{\left(u \right)}$
    So, the result is: $\frac{\sin{\left(u \right)}}{2}$
  Now substitute $u$ back in:
  
  $\frac{\sin{\left(2 x \right)}}{2}$
So, the result is: $- \frac{\sin{\left(2 x \right)}}{2}$
Add the constant of integration:

$- \frac{\sin{\left(2 x \right)}}{2}+ \mathrm{constant}$

The answer is:

- \frac{\sin{\left(2 x \right)}}{2}+ \mathrm{constant}

The answer (Indefinite) [src]

  /                           
 |                    sin(2*x)
 | -cos(2*x) dx = C - --------
 |                       2    
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\int \left(- \cos{\left(2 x \right)}\right)\, dx = C - \frac{\sin{\left(2 x \right)}}{2}

Simplify

The graph

Plot the graph f(x)

The answer [src]

-sin(2) 
--------
   2

- \frac{\sin{\left(2 \right)}}{2}

-sin(2) 
--------
   2

- \frac{\sin{\left(2 \right)}}{2}

-sin(2)/2

Numerical answer [src]

-0.454648713412841

-0.454648713412841

The graph

Use the examples entering the upper and lower limits of integration.