Integral of log2(x) dx
The solution
Detail solution
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The integral of a constant times a function is the constant times the integral of the function:
∫log(2)log(x)dx=log(2)∫log(x)dx
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Use integration by parts:
∫udv=uv−∫vdu
Let u(x)=log(x) and let dv(x)=1.
Then du(x)=x1.
To find v(x):
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The integral of a constant is the constant times the variable of integration:
∫1dx=x
Now evaluate the sub-integral.
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The integral of a constant is the constant times the variable of integration:
∫1dx=x
So, the result is: log(2)xlog(x)−x
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Now simplify:
log(2)x(log(x)−1)
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Add the constant of integration:
log(2)x(log(x)−1)+constant
The answer is:
log(2)x(log(x)−1)+constant
The answer (Indefinite)
[src]
/
|
| log(x) -x + x*log(x)
| ------ dx = C + -------------
| log(2) log(2)
|
/
log2xlogx−x
−log21
=
−log(2)1
Use the examples entering the upper and lower limits of integration.