Integral of e^-x dx
The solution
Detail solution
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Let u=−x.
Then let du=−dx and substitute −du:
∫(−eu)du
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The integral of a constant times a function is the constant times the integral of the function:
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The integral of the exponential function is itself.
∫eudu=eu
So, the result is: −eu
Now substitute u back in:
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Add the constant of integration:
−e−x+constant
The answer is:
−e−x+constant
The answer (Indefinite)
[src]
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| -x -x
| E dx = C - e
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∫e−xdx=C−e−x
The graph
Use the examples entering the upper and lower limits of integration.