Integral of cos(x)*exp(sin(x))*sin(x) dx
The solution
Detail solution
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Let u=sin(x).
Then let du=cos(x)dx and substitute du:
∫ueudu
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Use integration by parts:
∫udv=uv−∫vdu
Let u(u)=u and let dv(u)=eu.
Then du(u)=1.
To find v(u):
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The integral of the exponential function is itself.
∫eudu=eu
Now evaluate the sub-integral.
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The integral of the exponential function is itself.
∫eudu=eu
Now substitute u back in:
esin(x)sin(x)−esin(x)
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Now simplify:
(sin(x)−1)esin(x)
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Add the constant of integration:
(sin(x)−1)esin(x)+constant
The answer is:
(sin(x)−1)esin(x)+constant
The answer (Indefinite)
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| sin(x) sin(x) sin(x)
| cos(x)*e *sin(x) dx = C - e + e *sin(x)
|
/
∫esin(x)cos(x)sin(x)dx=C+esin(x)sin(x)−esin(x)
The graph
sin(1) sin(1)
1 - e + e *sin(1)
−esin(1)+1+esin(1)sin(1)
=
sin(1) sin(1)
1 - e + e *sin(1)
−esin(1)+1+esin(1)sin(1)
1 - exp(sin(1)) + exp(sin(1))*sin(1)
Use the examples entering the upper and lower limits of integration.