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- Improper integral
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How to use it?
- Integral of d{x}:
- Integral of √(1+sinx)
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Integral of senx/cos^2x
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Integral of sqrt(x)/x
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Integral of sin(2x)^2
- How do you in partial fractions?:
- 1/(x^3-1)^2
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Identical expressions
- one /(x^ three - one)^ two
- 1 divide by (x cubed minus 1) squared
- one divide by (x to the power of three minus one) to the power of two
- 1/(x3-1)2
- 1/x3-12
- 1/(x³-1)²
- 1/(x to the power of 3-1) to the power of 2
- 1/x^3-1^2
- 1 divide by (x^3-1)^2
- 1/(x^3-1)^2dx
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Similar expressions
- 1/(x^3+1)^2
Integral of 1/(x^3-1)^2 dx
The solution
You have entered
[src]
1 / | | 1 | --------- dx | 2 | / 3 \ | \x - 1/ | / 0
$$\int\limits_{0}^{1} \frac{1}{\left(x^{3} - 1\right)^{2}}\, dx$$
Integral(1/((x^3 - 1)^2), (x, 0, 1))
The graph
The answer
[src]
2*pi*I
oo + ------
9
$$\infty + \frac{2 i \pi}{9}$$
=
=
2*pi*I
oo + ------
9
$$\infty + \frac{2 i \pi}{9}$$
oo + 2*pi*i/9
The graph
Use the examples entering the upper and lower limits of integration.