Integral of 4xdx dx
The solution
Detail solution
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The integral of a constant times a function is the constant times the integral of the function:
∫4x1dx=4∫xdx
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The integral of xn is n+1xn+1 when n=−1:
∫xdx=2x2
So, the result is: 2x2
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Add the constant of integration:
2x2+constant
The answer is:
2x2+constant
The answer (Indefinite)
[src]
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| 2
| 4*x*1 dx = C + 2*x
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∫4x1dx=C+2x2
The graph
Use the examples entering the upper and lower limits of integration.