Given the inequality:
$$\frac{\sin{\left(x \right)}}{4} < \frac{\left(-1\right) \sqrt{3}}{2}$$
To solve this inequality, we must first solve the corresponding equation:
$$\frac{\sin{\left(x \right)}}{4} = \frac{\left(-1\right) \sqrt{3}}{2}$$
Solve:
Given the equation
$$\frac{\sin{\left(x \right)}}{4} = \frac{\left(-1\right) \sqrt{3}}{2}$$
- this is the simplest trigonometric equation
Divide both parts of the equation by 1/4
The equation is transformed to
$$\sin{\left(x \right)} = - 2 \sqrt{3}$$
As right part of the equation
modulo =
True
but sin
can no be more than 1 or less than -1
so the solution of the equation d'not exist.
$$x_{1} = \pi + \operatorname{asin}{\left(2 \sqrt{3} \right)}$$
$$x_{2} = - \operatorname{asin}{\left(2 \sqrt{3} \right)}$$
Exclude the complex solutions:
This equation has no roots,
this inequality is executed for any x value or has no solutions
check it
subtitute random point x, for example
x0 = 0
$$\frac{\sin{\left(0 \right)}}{4} < \frac{\left(-1\right) \sqrt{3}}{2}$$
___
-\/ 3
0 < -------
2
but
___
-\/ 3
0 > -------
2
so the inequality has no solutions