sin(x/4)<sqrt-(3/2) inequation

Mister Exam

Lang:

How to use it?
Inequation:
2*(x-1)-3*(x-2)<x
(x-1/4)(x-8)>=0
(1/2)^(2x+1)<4
5x^2-2x^4+7>0
Graphing y =:
sin(x/4)
Derivative of:
sin(x/4)
Integral of d{x}:
sin(x/4)
Identical expressions
sin(x/ four)<sqrt-(three / two)
sinus of (x divide by 4) less than square root of minus (3 divide by 2)
sinus of (x divide by four) less than square root of minus (three divide by two)
sin(x/4)<√-(3/2)
sinx/4<sqrt-3/2
sin(x divide by 4)<sqrt-(3 divide by 2)
Similar expressions
sin(x/4-3)<1/2
sin(x/4-3)<=(-sqrt(2))/2
sin(x/4)<sqrt+(3/2)
sin(x)>=sqrt-3/2
sin(x/2)<sqrt-(3)/2
sin(x)/4<-(3)^(1/2)/2
cos(x/2)<=sqrt-3/2
sin(x)>sqrt-3/2

   /x\     ___   3
sin|-| < \/ x  - -
   \4/           2

\sin{\left(\frac{x}{4} \right)} < \sqrt{x} - \frac{3}{2}

sin(x/4) < sqrt(x) - 3/2

Solving inequality on a graph