Given the inequality:
$$- \frac{x}{4} + \frac{2 x}{3} \leq -2$$
To solve this inequality, we must first solve the corresponding equation:
$$- \frac{x}{4} + \frac{2 x}{3} = -2$$
Solve:
Given the linear equation:
2*x/3-(x)*1/4 = -2
Expand brackets in the left part
2*x/3-x*1/4 = -2
Looking for similar summands in the left part:
5*x/12 = -2
Divide both parts of the equation by 5/12
x = -2 / (5/12)
$$x_{1} = - \frac{24}{5}$$
$$x_{1} = - \frac{24}{5}$$
This roots
$$x_{1} = - \frac{24}{5}$$
is the points with change the sign of the inequality expression.
First define with the sign to the leftmost point:
$$x_{0} \leq x_{1}$$
For example, let's take the point
$$x_{0} = x_{1} - \frac{1}{10}$$
=
$$- \frac{24}{5} + - \frac{1}{10}$$
=
$$- \frac{49}{10}$$
substitute to the expression
$$- \frac{x}{4} + \frac{2 x}{3} \leq -2$$
$$\frac{\left(- \frac{49}{10}\right) 2}{3} - \frac{-49}{4 \cdot 10} \leq -2$$
-49
---- <= -2
24
the solution of our inequality is:
$$x \leq - \frac{24}{5}$$
_____
\
-------•-------
x1