Mister Exam
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-
How to use it?
- Graphing y =:
- x^3-4x^2+3x
- -x^3+3x+1
- x^2+x+1
- x^2+4x+4
- Derivative of:
-
arcsin(1/x)
- Integral of d{x}:
- arcsin(1/x)
-
Identical expressions
- arcsin(one /x)
- arc sinus of (1 divide by x)
- arc sinus of (one divide by x)
- arcsin1/x
- arcsin(1 divide by x)
-
Similar expressions
- arcsin1/x
- arcsin(1/x^2)
- (x-1)/2+arcsin(1/(x-1))
Graphing y = arcsin(1/x)
The solution
You have entered
[src]
/1\
f(x) = asin|-|
\x/
$$f{\left(x \right)} = \operatorname{asin}{\left(\frac{1}{x} \right)}$$
f = asin(1/x)
The graph of the function
The domain of the function
The points at which the function is not precisely defined:
$$x_{1} = 0$$
$$x_{1} = 0$$
The points of intersection with the X-axis coordinate
Graph of the function intersects the axis X at f = 0
so we need to solve the equation:
$$\operatorname{asin}{\left(\frac{1}{x} \right)} = 0$$
Solve this equation
Solution is not found,
it's possible that the graph doesn't intersect the axis X
so we need to solve the equation:
$$\operatorname{asin}{\left(\frac{1}{x} \right)} = 0$$
Solve this equation
Solution is not found,
it's possible that the graph doesn't intersect the axis X
Extrema of the function
In order to find the extrema, we need to solve the equation
$$\frac{d}{d x} f{\left(x \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x} f{\left(x \right)} = $$
the first derivative
$$- \frac{1}{x^{2} \sqrt{1 - \frac{1}{x^{2}}}} = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
$$\frac{d}{d x} f{\left(x \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x} f{\left(x \right)} = $$
the first derivative
$$- \frac{1}{x^{2} \sqrt{1 - \frac{1}{x^{2}}}} = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
Inflection points
Let's find the inflection points, we'll need to solve the equation for this
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = $$
the second derivative
$$\frac{2 + \frac{1}{x^{2} \left(1 - \frac{1}{x^{2}}\right)}}{x^{3} \sqrt{1 - \frac{1}{x^{2}}}} = 0$$
Solve this equation
The roots of this equation
$$x_{1} = - \frac{\sqrt{2}}{2}$$
$$x_{2} = \frac{\sqrt{2}}{2}$$
You also need to calculate the limits of y '' for arguments seeking to indeterminate points of a function:
Points where there is an indetermination:
$$x_{1} = 0$$
$$\lim_{x \to 0^-}\left(\frac{2 + \frac{1}{x^{2} \left(1 - \frac{1}{x^{2}}\right)}}{x^{3} \sqrt{1 - \frac{1}{x^{2}}}}\right) = \infty i$$
$$\lim_{x \to 0^+}\left(\frac{2 + \frac{1}{x^{2} \left(1 - \frac{1}{x^{2}}\right)}}{x^{3} \sqrt{1 - \frac{1}{x^{2}}}}\right) = - \infty i$$
- the limits are not equal, so
$$x_{1} = 0$$
- is an inflection point
Сonvexity and concavity intervals:
Let’s find the intervals where the function is convex or concave, for this look at the behaviour of the function at the inflection points:
Have no bends at the whole real axis
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = $$
the second derivative
$$\frac{2 + \frac{1}{x^{2} \left(1 - \frac{1}{x^{2}}\right)}}{x^{3} \sqrt{1 - \frac{1}{x^{2}}}} = 0$$
Solve this equation
The roots of this equation
$$x_{1} = - \frac{\sqrt{2}}{2}$$
$$x_{2} = \frac{\sqrt{2}}{2}$$
You also need to calculate the limits of y '' for arguments seeking to indeterminate points of a function:
Points where there is an indetermination:
$$x_{1} = 0$$
$$\lim_{x \to 0^-}\left(\frac{2 + \frac{1}{x^{2} \left(1 - \frac{1}{x^{2}}\right)}}{x^{3} \sqrt{1 - \frac{1}{x^{2}}}}\right) = \infty i$$
$$\lim_{x \to 0^+}\left(\frac{2 + \frac{1}{x^{2} \left(1 - \frac{1}{x^{2}}\right)}}{x^{3} \sqrt{1 - \frac{1}{x^{2}}}}\right) = - \infty i$$
- the limits are not equal, so
$$x_{1} = 0$$
- is an inflection point
Сonvexity and concavity intervals:
Let’s find the intervals where the function is convex or concave, for this look at the behaviour of the function at the inflection points:
Have no bends at the whole real axis
Vertical asymptotes
Have:
$$x_{1} = 0$$
$$x_{1} = 0$$
Horizontal asymptotes
Let’s find horizontal asymptotes with help of the limits of this function at x->+oo and x->-oo
$$\lim_{x \to -\infty} \operatorname{asin}{\left(\frac{1}{x} \right)} = 0$$
Let's take the limit
so,
equation of the horizontal asymptote on the left:
$$y = 0$$
$$\lim_{x \to \infty} \operatorname{asin}{\left(\frac{1}{x} \right)} = 0$$
Let's take the limit
so,
equation of the horizontal asymptote on the right:
$$y = 0$$
$$\lim_{x \to -\infty} \operatorname{asin}{\left(\frac{1}{x} \right)} = 0$$
Let's take the limit
so,
equation of the horizontal asymptote on the left:
$$y = 0$$
$$\lim_{x \to \infty} \operatorname{asin}{\left(\frac{1}{x} \right)} = 0$$
Let's take the limit
so,
equation of the horizontal asymptote on the right:
$$y = 0$$
Inclined asymptotes
Inclined asymptote can be found by calculating the limit of asin(1/x), divided by x at x->+oo and x ->-oo
$$\lim_{x \to -\infty}\left(\frac{\operatorname{asin}{\left(\frac{1}{x} \right)}}{x}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the right
$$\lim_{x \to \infty}\left(\frac{\operatorname{asin}{\left(\frac{1}{x} \right)}}{x}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the left
$$\lim_{x \to -\infty}\left(\frac{\operatorname{asin}{\left(\frac{1}{x} \right)}}{x}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the right
$$\lim_{x \to \infty}\left(\frac{\operatorname{asin}{\left(\frac{1}{x} \right)}}{x}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the left
Even and odd functions
Let's check, whether the function even or odd by using relations f = f(-x) и f = -f(-x).
So, check:
$$\operatorname{asin}{\left(\frac{1}{x} \right)} = - \operatorname{asin}{\left(\frac{1}{x} \right)}$$
- No
$$\operatorname{asin}{\left(\frac{1}{x} \right)} = \operatorname{asin}{\left(\frac{1}{x} \right)}$$
- Yes
so, the function
is
odd
So, check:
$$\operatorname{asin}{\left(\frac{1}{x} \right)} = - \operatorname{asin}{\left(\frac{1}{x} \right)}$$
- No
$$\operatorname{asin}{\left(\frac{1}{x} \right)} = \operatorname{asin}{\left(\frac{1}{x} \right)}$$
- Yes
so, the function
is
odd