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arcsin(1/x^2)
  • How to use it?

  • Graphing y =:
  • -x^3+3x+2
  • x^3-3*x-2
  • -x^3-3x^2+3
  • x^3-3x^2+2x+1
  • Identical expressions

  • arcsin(one /x^ two)
  • arc sinus of (1 divide by x squared )
  • arc sinus of (one divide by x to the power of two)
  • arcsin(1/x2)
  • arcsin1/x2
  • arcsin(1/x²)
  • arcsin(1/x to the power of 2)
  • arcsin1/x^2
  • arcsin(1 divide by x^2)

Graphing y = arcsin(1/x^2)

v

The graph:

from to

Intersection points:

does show?

Piecewise:

The solution

You have entered [src]
           /  1 \
f(x) = asin|1*--|
           |   2|
           \  x /
$$f{\left(x \right)} = \operatorname{asin}{\left(1 \cdot \frac{1}{x^{2}} \right)}$$
f = asin(1/x^2)
The graph of the function
The domain of the function
The points at which the function is not precisely defined:
$$x_{1} = 0$$
The points of intersection with the X-axis coordinate
Graph of the function intersects the axis X at f = 0
so we need to solve the equation:
$$\operatorname{asin}{\left(1 \cdot \frac{1}{x^{2}} \right)} = 0$$
Solve this equation
Solution is not found,
it's possible that the graph doesn't intersect the axis X
The points of intersection with the Y axis coordinate
The graph crosses Y axis when x equals 0:
substitute x = 0 to asin(1/x^2).
$$\operatorname{asin}{\left(1 \cdot \frac{1}{0^{2}} \right)}$$
The result:
$$f{\left(0 \right)} = \tilde{\infty}$$
sof doesn't intersect Y
Extrema of the function
In order to find the extrema, we need to solve the equation
$$\frac{d}{d x} f{\left(x \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x} f{\left(x \right)} = $$
the first derivative
$$- \frac{2}{x^{3} \sqrt{1 - \frac{1}{x^{4}}}} = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
Inflection points
Let's find the inflection points, we'll need to solve the equation for this
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = $$
the second derivative
$$\frac{2 \cdot \left(3 + \frac{2}{x^{4} \cdot \left(1 - \frac{1}{x^{4}}\right)}\right)}{x^{4} \sqrt{1 - \frac{1}{x^{4}}}} = 0$$
Solve this equation
The roots of this equation
$$x_{1} = - \frac{3^{\frac{3}{4}}}{3}$$
$$x_{2} = \frac{3^{\frac{3}{4}}}{3}$$
You also need to calculate the limits of y '' for arguments seeking to indeterminate points of a function:
Points where there is an indetermination:
$$x_{1} = 0$$

$$\lim_{x \to 0^-}\left(\frac{2 \cdot \left(3 + \frac{2}{x^{4} \cdot \left(1 - \frac{1}{x^{4}}\right)}\right)}{x^{4} \sqrt{1 - \frac{1}{x^{4}}}}\right) = - \infty i$$
Let's take the limit
$$\lim_{x \to 0^+}\left(\frac{2 \cdot \left(3 + \frac{2}{x^{4} \cdot \left(1 - \frac{1}{x^{4}}\right)}\right)}{x^{4} \sqrt{1 - \frac{1}{x^{4}}}}\right) = - \infty i$$
Let's take the limit
- limits are equal, then skip the corresponding point

Сonvexity and concavity intervals:
Let’s find the intervals where the function is convex or concave, for this look at the behaviour of the function at the inflection points:
Have no bends at the whole real axis
Vertical asymptotes
Have:
$$x_{1} = 0$$
Horizontal asymptotes
Let’s find horizontal asymptotes with help of the limits of this function at x->+oo and x->-oo
$$\lim_{x \to -\infty} \operatorname{asin}{\left(1 \cdot \frac{1}{x^{2}} \right)} = 0$$
Let's take the limit
so,
equation of the horizontal asymptote on the left:
$$y = 0$$
$$\lim_{x \to \infty} \operatorname{asin}{\left(1 \cdot \frac{1}{x^{2}} \right)} = 0$$
Let's take the limit
so,
equation of the horizontal asymptote on the right:
$$y = 0$$
Inclined asymptotes
Inclined asymptote can be found by calculating the limit of asin(1/x^2), divided by x at x->+oo and x ->-oo
$$\lim_{x \to -\infty}\left(\frac{\operatorname{asin}{\left(1 \cdot \frac{1}{x^{2}} \right)}}{x}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the right
$$\lim_{x \to \infty}\left(\frac{\operatorname{asin}{\left(1 \cdot \frac{1}{x^{2}} \right)}}{x}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the left
Even and odd functions
Let's check, whether the function even or odd by using relations f = f(-x) и f = -f(-x).
So, check:
$$\operatorname{asin}{\left(1 \cdot \frac{1}{x^{2}} \right)} = \operatorname{asin}{\left(1 \cdot \frac{1}{x^{2}} \right)}$$
- Yes
$$\operatorname{asin}{\left(1 \cdot \frac{1}{x^{2}} \right)} = - \operatorname{asin}{\left(1 \cdot \frac{1}{x^{2}} \right)}$$
- No
so, the function
is
even
The graph
Graphing y = arcsin(1/x^2)