The teacher will be very surprised to see your correct solution 😉

Detail solution

Given the linear equation:

Looking for similar summands in the left part:

Move the summands with the other variables

from left part to right part, we given:

$$5 x = 20 - 5 y$$

Divide both parts of the equation by 5

We get the answer: x = 4 - y

5*x+5*y = 20

Looking for similar summands in the left part:

5*x + 5*y = 20

Move the summands with the other variables

from left part to right part, we given:

$$5 x = 20 - 5 y$$

Divide both parts of the equation by 5

x = 20 - 5*y / (5)

We get the answer: x = 4 - y

Rapid solution
[src]

x1 = 4 - re(y) - I*im(y)

$$x_{1} = - \operatorname{re}{\left(y\right)} - i \operatorname{im}{\left(y\right)} + 4$$

x1 = -re(y) - i*im(y) + 4