Mister Exam
Other calculators
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How to use it?
- Equation:
- Equation 1-y^2=2+x
-
Equation 1-7*(4+2*x)=-9-4*x
-
Equation 2*cos(x)+1=0
-
Equation 3x-2=5
- Express {x} in terms of y where:
- 17*x-18*y=10
- -7*x+7*y=-14
- 10*x-16*y=6
- 1*x-4*y=1
- Integral of d{x}:
- 12-2x
-
Identical expressions
- twelve -2x= three (three -2x)- thirteen
- 12 minus 2x equally 3(3 minus 2x) minus 13
- twelve minus 2x equally three (three minus 2x) minus thirteen
- 12-2x=33-2x-13
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Similar expressions
- 5x-12-2(x-1)=3(5-2x)+4x
- (4x-1)2-2x(8x-3)=3
- x^2/(x+1)^2-2x/(x+1)+1=0
- 12-2*(x+3)=26
- 12-2x=3(3-2x)+13
- 12+2x=3(3-2x)-13
- 12-2x=3(3+2x)-13
12-2x=3(3-2x)-13 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the right part
Looking for similar summands in the right part:
Move free summands (without x)
from left part to right part, we given:
$$- 2 x = - 6 x - 16$$
Move the summands with the unknown x
from the right part to the left part:
$$4 x = -16$$
Divide both parts of the equation by 4
We get the answer: x = -4
12-2*x = 3*(3-2*x)-13
Expand brackets in the right part
12-2*x = 3*3-3*2*x-13
Looking for similar summands in the right part:
12 - 2*x = -4 - 6*x
Move free summands (without x)
from left part to right part, we given:
$$- 2 x = - 6 x - 16$$
Move the summands with the unknown x
from the right part to the left part:
$$4 x = -16$$
Divide both parts of the equation by 4
x = -16 / (4)
We get the answer: x = -4
The graph