Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 17x-8=20x+7
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Equation 2*x^2+6*x+9=
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Equation (x-2)^2=(x-9)^2
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Equation -x=8
- Express {x} in terms of y where:
- 17*x+20*y=-12
- 17*x+16*y=7
- -5*x+6*y=19
- 18*x-14*y=-12
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Identical expressions
- five x- twelve - two (x- one)= three (5-2x)+4x
- 5x minus 12 minus 2(x minus 1) equally 3(5 minus 2x) plus 4x
- five x minus twelve minus two (x minus one) equally three (5 minus 2x) plus 4x
- 5x-12-2x-1=35-2x+4x
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Similar expressions
- 5x-12-2(x+1)=3(5-2x)+4x
- 5x-12+2(x-1)=3(5-2x)+4x
- 5x-12-2(x-1)=3(5-2x)-4x
- 5x-12-2(x-1)=3(5+2x)+4x
- 5x+12-2(x-1)=3(5-2x)+4x
5x-12-2(x-1)=3(5-2x)+4x equation
The teacher will be very surprised to see your correct solution 😉
The solution
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5*x - 12 - 2*(x - 1) = 3*(5 - 2*x) + 4*x
$$- 2 \left(x - 1\right) + \left(5 x - 12\right) = 4 x + 3 \left(5 - 2 x\right)$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Looking for similar summands in the left part:
Looking for similar summands in the right part:
Move free summands (without x)
from left part to right part, we given:
$$3 x = 25 - 2 x$$
Move the summands with the unknown x
from the right part to the left part:
$$5 x = 25$$
Divide both parts of the equation by 5
We get the answer: x = 5
5*x-12-2*(x-1) = 3*(5-2*x)+4*x
Expand brackets in the left part
5*x-12-2*x+2*1 = 3*(5-2*x)+4*x
Expand brackets in the right part
5*x-12-2*x+2*1 = 3*5-3*2*x+4*x
Looking for similar summands in the left part:
-10 + 3*x = 3*5-3*2*x+4*x
Looking for similar summands in the right part:
-10 + 3*x = 15 - 2*x
Move free summands (without x)
from left part to right part, we given:
$$3 x = 25 - 2 x$$
Move the summands with the unknown x
from the right part to the left part:
$$5 x = 25$$
Divide both parts of the equation by 5
x = 25 / (5)
We get the answer: x = 5