1-y^2=2+x equation
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The solution
Detail solution
Given the linear equation:
1-y^2 = 2+x
Move free summands (without x)
from left part to right part, we given:
$$- y^{2} = x + 1$$
Move the summands with the unknown x
from the right part to the left part:
$$- y^{2} - x = 1$$
Divide both parts of the equation by (-x - y^2)/x
x = 1 / ((-x - y^2)/x)
We get the answer: x = -1 - y^2
Sum and product of roots
[src]
$$\left(- y^{2} - 1\right) + 0$$
$$- y^{2} - 1$$
$$1 \left(- y^{2} - 1\right)$$
$$- y^{2} - 1$$