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1-y^2=2+x equation

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Numerical solution:

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The solution

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     2        
1 - y  = 2 + x
$$- y^{2} + 1 = x + 2$$
Detail solution
Given the linear equation:
1-y^2 = 2+x

Move free summands (without x)
from left part to right part, we given:
$$- y^{2} = x + 1$$
Move the summands with the unknown x
from the right part to the left part:
$$- y^{2} - x = 1$$
Divide both parts of the equation by (-x - y^2)/x
x = 1 / ((-x - y^2)/x)

We get the answer: x = -1 - y^2
The graph
Rapid solution [src]
           2
x1 = -1 - y 
$$x_{1} = - y^{2} - 1$$
Sum and product of roots [src]
sum
          2
0 + -1 - y 
$$\left(- y^{2} - 1\right) + 0$$
=
      2
-1 - y 
$$- y^{2} - 1$$
product
  /      2\
1*\-1 - y /
$$1 \left(- y^{2} - 1\right)$$
=
      2
-1 - y 
$$- y^{2} - 1$$
-1 - y^2