Mister Exam
Other calculators
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How to use it?
- Equation:
-
Equation cos(8x)=-(1/2)
- Equation (13+x)×12=80
- Equation (3y+2)/(4y^2+y)+(y-3)/(16y^2-1)=3/(4y-1)
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Equation x^4−13x^2+36=0.
- Express {x} in terms of y where:
- 5*x-5*y=20
- 8*x-7*y=-13
- 15*x-15*y=16
- 9*x+18*y=6
- Integral of d{x}:
- 80
- Sum of series:
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80
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Identical expressions
- (thirteen +x)× twelve = eighty
- (13 plus x)×12 equally 80
- (thirteen plus x)× twelve equally eighty
- 13+x×12=80
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Similar expressions
- (13-x)×12=80
(13+x)×12=80 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Move free summands (without x)
from left part to right part, we given:
$$12 x = -76$$
Divide both parts of the equation by 12
We get the answer: x = -19/3
(13+x)*12 = 80
Expand brackets in the left part
13*12+x*12 = 80
Move free summands (without x)
from left part to right part, we given:
$$12 x = -76$$
Divide both parts of the equation by 12
x = -76 / (12)
We get the answer: x = -19/3
Sum and product of roots
[src]
sum
-19/3
$$- \frac{19}{3}$$
=
-19/3
$$- \frac{19}{3}$$
product
-19/3
$$- \frac{19}{3}$$
=
-19/3
$$- \frac{19}{3}$$
-19/3